Solution :
Given
Now,
Therefore,
Given,
= 2 + 0.368
= 2.368 min
At user equilibrium,
∴ = 2.368 min
= 1368 veh/h
12.50 An air conditioner operating at steady state takes in moist air at 28°C, 1 bar, and 70% relative humidity. The moist air f
irst passes over a cooling coil in the dehumidifier unit and some water vapor is condensed. The rate of heat transfer between the moist air and the cooling coil is 11 tons. Saturated moist air and condensate streams exit the dehumidifier unit at the same temperature. The moist air then passes through a heating unit, exiting at 24°C, 1 bar, and 40% relative humidity. Neglecting kinetic and potential energy effects, determine a. the temperature of the moist air exiting the dehumidifier unit, in °C. b. the volumetric flow rate of the air entering the air conditioner, in m3/min. c. the rate water is condensed, in kg/min. d. the rate of heat transfer to the air passing through the heating unit, in kW.
1 answer:
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