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fomenos
3 years ago
11

Mark each one as either Potential or Kinetic Energy?

Engineering
1 answer:
never [62]3 years ago
3 0
A- kinety
b- potential
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3 years ago
Find the second derivative of: y = sqrt(x + 4)/4; x ≥ -4.
hammer [34]

Answer: \dfrac{-1}{16(x+4)^{\frac{3}{2}}}

Explanation:

Given

y=\dfrac{\sqrt{x+4}}{4}\\\text{differentitate w.r.t x}\\\dfrac{\mathrm{d} y}{\mathrm{d} x}=\dfrac{1}{4}\times \dfrac{1}{2\sqrt{x+4}}=\dfrac{1}{8\sqrt{x+4}}

\dfrac{\mathrm{d} y}{\mathrm{d} x}=\dfrac{(x+4)^{-0.5}}{8}

Again differentiate for the second derivative

\frac{\mathrm{d^2} y}{\mathrm{d} x^2}=\dfrac{1}{8}\times \dfrac{-1}{2(x+4)^{\frac{3}{2}}}=\dfrac{-1}{16(x+4)^{\frac{3}{2}}}

8 0
4 years ago
Read 2 more answers
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