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svet-max [94.6K]
3 years ago
7

A wind generator, such as the one shown , uses the power of wind to generate electricity What do you think is happening inside t

he wind generator to convert the energy of the spinning blades into electricity? Make your best guess.

Physics
2 answers:
sesenic [268]3 years ago
8 0

Answer:

A wind turbine captures the wind, which then produces a renewable energy source. The wind makes the rotor spin; as the rotor spins, the movement of the blades drives a generator that creates energy. The motion of the blades turning is kinetic energy. It is this power that we convert into electricity.

lesya [120]3 years ago
4 0

Answer:

Explanation:

wires move through an electric field and create an electrical current

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Solving 2-D Motion
Lesechka [4]

do you have a formulai can do this problem

3 0
3 years ago
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While watching a small fireworks display from a building 204 feet tall, you observe a rocket that travels from ground to eye lev
faltersainse [42]
204 ft = 62.2 m
We know that the initial velocity of the rocket was 0, we can find its acceleration using:
s = ut + 1/2 at²
62.2 = 0.5a(6)²
a = 3.46 m/s²
Now, the final velocity of the rocket:
v = u + at
v = 3.46 x 6
v = 20.76 m/s = 68.1 ft/s
4 0
2 years ago
While skydiving, your parachute opens and you slow from 50.0 m/s to 8.0 m/s in 0.75 s . Determine the distance you fall while th
Anestetic [448]

Answer:

21.75 m

Explanation:

t = Time taken for the car to slow down = 0.75 s

u = Initial velocity = 50 m/s

v = Final velocity = 8 m/s

s = Displacement

a = Acceleration

Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{8-50}{0.75}\\\Rightarrow a=-56\ m/s^2

Acceleration is -56 m/s²

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{8^2-50^2}{2\times -56}\\\Rightarrow s=21.75\ m

The distance covered in the 0.75 seconds is 21.75 m

8 0
3 years ago
A physicist is calibrating a spectrometer that uses a diffraction grating to separate light in order of increasing wavelength (λ
cluponka [151]

Answer:

Explanation:

Given

N=3680 cm^{-1}

therefore slit spacing d=\frac{1}{N}=\frac{1}{3680}=2.717\times 10^{-4}\ cm

since d\sin \theta =n\lambda

for n=1

d\sin \theta =\lambda

Now,at \theta _1=12.9^{\circ},\Rightarrow \lambda _1=6.0657\times 10^{-7}\ m=606.57\ nm

at \theta _2=14.2^{\circ}\Rightarrow \lambda_2=666.5\ nm

at \theta _3=15^{\circ}\Rightarrow \lambda_3=703.21\ nm

5 0
2 years ago
A 97.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 48.0 m/s. If both are initially at rest and if t
OverLord2011 [107]

Answer:

s₁ = 0.022 m

Explanation:

From the law of conservation of momentum:

m_1u_1 + m_2u_2 = m_1v_1+m_2v_2

where,

m₁ = mass of hockey player = 97 kg

m₂ = mass of puck = 0.15 kg

u₁ = u₂ = initial velocities of puck and player = 0 m/s

v₁ = velocity of player after collision = ?

v₂ = velocity of puck after hitting = 48 m/s

Therefore,

(97\ kg)(0\ m/s)+(0.15\ kg)(0\ m/s)=(97\ kg)(v_1)+(0.15\ kg)(48\ m/s)\\\\v_1 = -\frac{(0.15\ kg)(48\ m/s)}{97\ kg} \\v_1 = - 0.074 m/s

negative sign here shows the opposite direction.

Now, we calculate the time taken by puck to move 14.5 m:

s_2 =v_2t\\\\t = \frac{s_2}{v_2} = \frac{14.5\ m}{48\ m/s} \\\\t =  0.3\ s

Now, the distance covered by the player in this time will be:

s_1 = v_1t\\s_1 = (0.074\ m/s)(0.3\ s)

<u>s₁ = 0.022 m</u>

4 0
2 years ago
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