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3 years ago

Einstein's mass / energy theory is expressed by the equation E =MC2. true false

Physics

2 answers:

lesya692 [45]3 years ago

4 0

True. E=energy M=mass c= speed of light

svlad2 [7]3 years ago

3 0

True............hope it helps

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A small Styrofoam bead with a charge of −60.0 nC is at the center of an insulating plastic spherical shell with an inner radius

Romashka-Z-Leto [24]

Answer:

speed of the proton is 6.286 × $10^{5}$ m/s

Explanation:

given data

charge q= −60.0 nC

inner radius a = 20.0 cm

outer radius b = 24.0 cm

charge density ρ = −2.05 µC/m³

to find out

What is the speed of the proton

solution

we know that force on the proton due to this electric field is express as

F = q × E ...................1

here F is force and q is charge and E is electric filed so

if v be the speed of the proton in circular orbit than force will be

F = $\frac{mv^2}{b}$ ....................2

from equation 1 and 2

q × E = $\frac{mv^2}{b}$ .......................3

here total charge Q on shell is

Q = ρ × V

here ρ is density and V is volume

Q = $\rho * \frac{4}{3} \pi (b^3-a^3)$

put here value

Q = $-2.05*10^{-6} \frac{4}{3} \pi (0.24^3-0.20^3)$

Q = 50.01 × $10^{-9}$ C

and

total charge enclosed by Gaussian surface is

qin = q + Q

qin = −60 × $10^{-9}$ C - 50.01 × $10^{-9}$ C

qin = - 110.01 × $10^{-9}$ C

and

from Gauss law

$\oint E*A = \frac{\left | qin \right | }{\epsilon }$

E ×4×π×b² = $\frac{110.01*10^{-9} }{\epsilon }$

E = $\frac{110.01*10^{-9} }{\epsilon *4 *\pi *b^2[tex]}$

E = $\frac{9*10^9 * 110.01*10^{-9} }{0.24^2}$

E = 17189.06 N/C

from equation 3

q × E = $\frac{mv^2}{b}$

v = $\sqrt{\frac{q*E*b}{m}}$

v = $\sqrt{\frac{1.6*10^{-19}*17189.06*0.24}{1.67*10^{-27}}}$

v = 6.286 × $10^{5}$ m/s

so speed of the proton is 6.286 × $10^{5}$ m/s

4 0

3 years ago

Which tools would Sara use to find and irregularly shaped objects mass in volume?

pogonyaev

To find the mass and volume of irregularly shaped object. One can use the balance to find the weight, and to find the volume of the object water should be poured in the beaker and note the level of water.

8 0

3 years ago

URNOW Lidl llIIS 15 TIUta WiCluie U water! ify-What two kinds of matter are pure substances?

Arada [10]

Elements and compounds

Explanation:

All pure substances are distinct substances.
All their parts are the same throughout i.e they are homogeneous.
They have a definite composition.
They cannot be easily separated or broken down into simpler substances by physical means.
They have a unique set of physical properties.

Elements are distinct substances that cannot be split up into simpler ones.

Compounds are substances composed of two or more kinds of atoms joined together in a definite grouping.

Learn more:

Elements in the universe brainly.com/question/4581837

#learnwithBrainly

6 0

3 years ago

A gas mixture contains 320mg methane, 175 mg argon, 225 mg nitrogen (N2). The partial pressure of argon at 300K is 12.52 kPa. Wh

svet-max [94.6K]

Answer: The volume and total pressure of the mixture is 0.876 L and 89.36 kPa respectively.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For methane:

Given mass of methane = 320 mg = 0.3 g (Conversion factor: 1 g = 1000 mg)

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of methane}=\frac{0.3g}{16g/mol}=0.019mol$

For argon:

Given mass of argon = 175 mg = 0.175 g

Molar mass of argon = 40 g/mol

Putting values in equation 1, we get:

$\text{Moles of argon}=\frac{0.175g}{40g/mol}=0.0044mol$

For nitrogen:

Given mass of nitrogen = 225 mg = 0.225 g

Molar mass of nitrogen = 28 g/mol

Putting values in equation 1, we get:

$\text{Moles of nitrogen}=\frac{0.225g}{28g/mol}=0.0080mol$

To calculate the volume of the mixture, we use the equation:

PV = nRT ......(2)

We are given:

Partial pressure of argon = 12.52 kPa

Temperature = 300 K

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

n = number of moles of argon = 0.0044 moles

Putting values in equation 2, we get:

$12.52kPa\times V=0.0044mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 300K\\\\V=\frac{0.0044\times 8.31\times 300}{12.52}=0.876L$

Now, calculating the total pressure of the mixture by using equation 2:

Total number of moles = [0.019 + 0.0044 + 0.0080] mol = 0.0314 mol

V= volume of the mixture = 0.876 L

Putting values in equation 2, we get:

$P\times 0.876L=0.0314mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 300K\\\\P=\frac{0.0341\times 8.31\times 300}{0.876}=89.36kPa$

Hence, the volume and total pressure of the mixture is 0.876 L and 89.36 kPa respectively.

5 0

3 years ago

A two-dimensional crystal has a rectangular unit cell, with spacings between the centers of the atoms of 0.5 nm in one direction

pav-90 [236]

So directly the cell density value in a rectangle is:

$5*10^{17} cells/cm^{2}$

In this exercise, we must first calculate the area of the rectangle, remembering that you need to convert from nm to cm is:

$A=B*H\\A=(0.4*10^{-7})*(0.5*10^{-7})= 2*10^{-15}$

Next, let's calculate the density from the calculated area:

$\frac{N}{A} = \frac{1000}{2*10^{-15} } = 5*10^{17}$

In this way, the calculation represents that there is:

$5*10^{17} cells/cm^{2}$

Learn more: brainly.com/question/18320053

6 0

3 years ago