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faltersainse [42]
3 years ago
15

Use the data in the table above to calculate an approximate ΔH∘ in kilojoules for the synthesis of hydrazine from ammonia:

Chemistry
1 answer:
dmitriy555 [2]3 years ago
7 0
On the left (reactant) side you have 6 N-H bonds and 1 Cl-Cl bond 
<span>On the right (product) side you have 4 N-H bonds, 1 N-N bond and 2 H-Cl bonds </span>

<span>Add up the bond energies for each side (multiplying by the number of bonds) and calculate the difference for your ΔHº</span>
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Another simple question and I need it bad
podryga [215]
Oh this is extremely hard...i might just die lol jk its the last one measuring cylinder :)
3 0
2 years ago
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An inexpensive and accurate method of measuring the quantity of electricity flowing through a circuit is to pass the current thr
Paha777 [63]

Total of 127.013 C of charge is passed

Given

 weight of Ag solution before current has passed = 1.7854 g

  weight of Ag solution after current has passed = 1.8016 g

  Molecular mass of Ag = 107.86 g

  Faraday's Constant = 96485

First of all we have to apply Faraday's First Law of Electrolysis i.e

         m = ZQ

  where

Z is propotionality constant (g/C)

Q is charge (C)

Hence,

 Z = Atomic mass of substance/ Faraday's Constant

    = \frac{107.86 g}{96485 C}

    = 0.0011178 g/C

Now ,

   change in mass before and after the passing of current (Δm)

       Δm = 1.8016g-1.7854g

             =   0.0162g

    Now  amount of coulombs passed = \frac{0.142g}{0.0011178 g/C }

          amount of coulombs passed = 127.03524 C

Thus from the above conclusion we can say that amount of coulombs have passed is 127.03524 C

Learn more about Electrolysis here: brainly.com/question/16929894

#SPJ4

7 0
1 year ago
How many grams does f Cacl2 should be dissolved in 750.0 mL of water to make a 0.100 M solution Cacl2
AVprozaik [17]

Answer:

8.324 g

Explanation:

First we <u>convert 750.0 mL into L</u>:

  • 750.0 mL / 1000 = 0.750 L

Then we <u>calculate the required number of moles of CaCl₂</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / liters
  • Molarity * liters = moles
  • 0.100 M * 0.750 L = 0.075 mol

Finally we <u>convert 0.075 moles of CaCl₂ into grams</u>, using its <em>molar mass</em>:

  • 0.075 mol * 110.98 g/mol = 8.324 g
6 0
2 years ago
Why would aluminum foil be useful in a thermos design
Pie
To be used as a conductor for heat
3 0
2 years ago
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How many moles are in 63 g of NH4 (molar mass= 18g)?
sdas [7]

To answer this question, all you to do is to divide the mass by the molar mass and that should get you your moles.

=63g\ NH_{4}\ x\ \frac{1\ mol\ NH_{4}}{18g\ NH_{4}}

<em>= 3.5 mol NH₄</em>

<em></em>

<em></em>

4 0
2 years ago
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