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yarga [219]
3 years ago
7

What three different equations that have x = 5 as a solution

Mathematics
2 answers:
Mars2501 [29]3 years ago
5 0
5x=25 could be one.
25/x-3=2 is another.
And the last one could be x/85+7=24
Vinvika [58]3 years ago
3 0
X+10 = 15

10x + 10 = 65

7x + 8(x²) = 235

hope this helps
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Find the measure of <6
eduard

Answer:

110 degrees

Step-by-step explanation:

Parallels lines, when intersected by a straight line, form congruent angles. Therefore 110 is equal to angle 6

4 0
3 years ago
Evaluate the function at the indicated values. f(x)= 6x^2+ 5x -12
seropon [69]

Step-by-step explanation:

We need to find the value of the function at the indicated value.

f(x)= 6x^2+ 5x -12

Indicated values are : f(-7), f(0), f(6), f(7)

To find f(-7), put x = -7 in the given function

f(-7)= 6(-7)^2+ 5(-7) -12=247

To find f(0), put x = 0 in the given function

f(0)= 6(0)^2+ 5(0) -12=-12

To find f(6), put x = 6 in the given function

f(6)= 6(6)^2+ 5(6) -12=234

To find f(7), put x = 7 in the given function

f(7)= 6(7)^2+ 5(7) -12=317

Hence, this is the required solution.

8 0
3 years ago
Lenny has a remaining balance on his credit card of $800. His credit card has an APR of 22 percent. How much will he pay in inte
olasank [31]

Answer:

22

Step-by-step explanation:

5 0
3 years ago
Picture is included. Please help me!!!
umka2103 [35]
I think its the one when it says 'all factors were negatives' because if u have -1 times -1 tmes -1 times -1, for -1 to the 4th power, the result will be a positive one
8 0
3 years ago
A ski jumper is preparing for her start on top of the jumping hill in korea which has a horizontal run of 234 meters. She sees t
slamgirl [31]

Answer:

The height of the jumping hill x = 189.3 m

Step-by-step explanation:

From Δ ABC

AB = x = height of the hill

∠A = 36° , ∠B = 90°

Thus ∠C = 180 - ∠A - ∠B

⇒ ∠C = 180 - 36 - 90

⇒ ∠C =  54°

From Δ ABC  

\sin 54 = \frac{AB}{AC}

\sin 54 = \frac{x}{234}

x = 0.809 × 234

x = 189.3 m

This is the height of the jumping hill.

4 0
3 years ago
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