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yarga [219]
3 years ago
7

What three different equations that have x = 5 as a solution

Mathematics
2 answers:
Mars2501 [29]3 years ago
5 0
5x=25 could be one.
25/x-3=2 is another.
And the last one could be x/85+7=24
Vinvika [58]3 years ago
3 0
X+10 = 15

10x + 10 = 65

7x + 8(x²) = 235

hope this helps
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The value of a car is $20,000. It loses 10.7% of its value every year . Find the approximate monthly decrease in value . Round y
jenyasd209 [6]

Answer:

$178.3

Step-by-step explanation:

The value of a car is $20,000

The car loses 10.7% of its value yearly

Since there are 12 months in a year then 10.7% can be represented as

10.7%/12

= 0.8916%

Therefore the approximate monthly decrease in value can be calculated as follows

= $20,000×0.8916/100

= $20,000×0.008916

= $178.3

Hence the approximate monthly decrease in value is $178.3

7 0
2 years ago
Help please!!!!!!!!!!!!!!
Lapatulllka [165]

Answer:

3(n + 2) > 0

Step-by-step explanation:

Work on a piece at a time.

"sum of a number and two": n + 2

"three times the sum of a number and two": 3(n + 2)

"three times the sum of a number and two is greater than zero": 3(n + 2) > 0

Answer: 3(n + 2) > 0

5 0
3 years ago
Please help me ASAP TYYY
uranmaximum [27]

Answer:

addition property

Step-by-step explanation:

See attached image.

7 0
1 year ago
Abigail starts work at 8:00 am and Zavier starts at 7:00 am. They both finish at the same time. If abigail works x hours, how ma
Tamiku [17]
X+1 Hours, because Zavier begins work an hour earlier than Abigail.
7 0
2 years ago
Read 2 more answers
How many years will it take for the account to reach $18,600? Round your answer to the nearest hundredth
Margarita [4]
 <span>it depends how the interest is calculated, but there's not much of a difference 

assuming its continuously compouned, you use this formula: A(t)=Pe^(rt), where A is the final amount, P is the initial investment, r is the interest, and t is the time in years 

you want to find t such that A(t)=18,600 so 18,600=1000e^(.0675t) 

you need to use logarithm to figure it out, take the natural log of both sides 

the following properties will come into use: 

ln(a*b)=ln(a)+ln(b) 
ln(a^b)=bln(a) 
ln(e)=1 

taking the natural log 

ln(18,600)=ln(1000e^(.0675t)) 

ln(18,600)=ln(1000)+ln(e^.0675t) 

ln(18600)=ln(1000) + .0675t 

now solve for t: t= (ln(18600)-ln(1000))/.0675 

t=43.31</span>
4 0
2 years ago
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