Answer:
$178.3
Step-by-step explanation:
The value of a car is $20,000
The car loses 10.7% of its value yearly
Since there are 12 months in a year then 10.7% can be represented as
10.7%/12
= 0.8916%
Therefore the approximate monthly decrease in value can be calculated as follows
= $20,000×0.8916/100
= $20,000×0.008916
= $178.3
Hence the approximate monthly decrease in value is $178.3
Answer:
3(n + 2) > 0
Step-by-step explanation:
Work on a piece at a time.
"sum of a number and two": n + 2
"three times the sum of a number and two": 3(n + 2)
"three times the sum of a number and two is greater than zero": 3(n + 2) > 0
Answer: 3(n + 2) > 0
Answer:
addition property
Step-by-step explanation:
See attached image.
X+1 Hours, because Zavier begins work an hour earlier than Abigail.
<span>it depends how the interest is calculated, but there's not much of a difference
assuming its continuously compouned, you use this formula: A(t)=Pe^(rt), where A is the final amount, P is the initial investment, r is the interest, and t is the time in years
you want to find t such that A(t)=18,600 so 18,600=1000e^(.0675t)
you need to use logarithm to figure it out, take the natural log of both sides
the following properties will come into use:
ln(a*b)=ln(a)+ln(b)
ln(a^b)=bln(a)
ln(e)=1
taking the natural log
ln(18,600)=ln(1000e^(.0675t))
ln(18,600)=ln(1000)+ln(e^.0675t)
ln(18600)=ln(1000) + .0675t
now solve for t: t= (ln(18600)-ln(1000))/.0675
t=43.31</span>