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fomenos
3 years ago
7

Heat from the sun causes ________________ of water from the ocean and land surfaces

Physics
1 answer:
Whitepunk [10]3 years ago
3 0
In this item, we are asked for the word that would best fit in the blank of the sentence given above. The word that is missing in this item is "<em>evaporation</em>".

Evaporation is part of the water cycle wherein the liquid molecule of water is converted to water vapor and stays in the atmosphere until it is converted back to water for precipitation. 
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In New Hampshire, people consumed an average of 39.8 gallons of beer in 2018, and the price per gallon was about $7.61. Suppose
sladkih [1.3K]

Answer:

Price elasticity of demand = 0.25

Explanation:

The detailed steps and appropriate derivation is as shown in the attached file.

8 0
3 years ago
How much heat is absorbed by 41 g iron skillet when its temperature varies from 9°C. to 20°C
alexgriva [62]

Answer:

202.95J

Explanation:

The formulae for the energy absorbed by the iron skillet is;

q=m*c*ΔФ   where q=energy absorbed, m is mass of iron skillet, c is specific heat capacity and ΔФ is change in temperature

Given that;

m= 41g

ΔФ=20°-9°=11°

c=0.45 J/g°C

q= 41×0.45×11

q= 202.95 J

4 0
3 years ago
Which answer below correctly identifies the type of change and the explanation for the heating of copper sulfate pentahydrate?
dolphi86 [110]

Answer:

chemical change because gas formation was observed along with a color change, which indicated that the copper sulfate pentahydrate was transformed into a different substance

Explanation:

i took a test

6 0
4 years ago
A ball is dropped from a boat so that it strikes the surface of a lake with a speed of 16.5 ft/s. While in the water, the ball e
denis23 [38]
The initial velocity is
v(0) = 16.5 ft/s

While in the water, the acceleration is
a(t) = 10 - 0.\frac{dv}{dt} =10-0.8v \\\\  \frac{dv}{10-0.8v}=dt \\\\ \int_{16.5}^{v} \,  \frac{dv}{10-0.8v}  = \int_{0}^{t} dt \\\\ - \frac{1}{0.8} [ln(10-0.8v)]_{16.5}^{v}=t \\\\ ln \frac{10-0.8v}{-3.2}=-0.8t \\\\  \frac{0.8v -10}{3.2}  =e^{-0.8t} \\\\ 0.8v = 10 + 3.2e^{-0.8t} \\\\ v=12.5+4e^{-0.08t}

The velocity function is
v(t)=12.5+4e^{-0.8t}
It satisfies the condition that v(0) = 16.5 ft/s.
When t = 5.7s, obtain
v(5.7)=12.5+4e^{-0.8\times5.7} = 12.54 \, ft/s

The depth of the lake is
d=\int_{0}^{5.7} \, (12.5+4e^{-0.8t})dt \\\\ = 12.5(5.7)+ \frac{4}{(-0.8)}[e^{-0.8t}]_{0}^{5.7} \\\\ =71.25-5(0.0105-1) =76.198 \, ft

Answer:
The velocity at the bottom of the lake is 12.5 ft/s
The depth of the lake is 76.2 ft


7 0
3 years ago
Last week we investigated the black hole at the center of our galaxy, with massMX= 8.5×1036kg. An object whose size is on the or
swat32

Answer:

d=2.38*10^{13}m

Explanation:

We know the mass of the hole, so we define as,

M_x= {8.5*10^{36}}kg

For which centripetal force is equal to gravitational force

\frac{mv^2}{r}=\frac{GMm}{d^2}

Angular velocity is equal to v/r,

w^2r=\frac{6.67*10^{-11}*8.5*10^{36}}{d^2}

As r=1 and w=1, we clear to d,

d^2=5.6695*10^{26}m

d=2.38*10^{13}m

6 0
4 years ago
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