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laiz [17]
3 years ago
8

A car, of mass 2.1 X 10^3 kg, travels in the horizontal plane around an unbanked curve of a radius of 275 m at a speed of 26 m/s

, without sliding.
a) Determine the minimum coefficient of static friction between the tires and the road.








b) How would your answer in part a) be affected if the mass of the vehicle were greater because of the presence of heavy cargo?





c) How would your answer in part a) be affected if the curve were sharper, i.e., if its radius were smaller?
Physics
1 answer:
Nadusha1986 [10]3 years ago
4 0

Answer:

Centripetal force is perpendicular to velocity and causes uniform circular motion. ... force exerted on a 900.0-kg car that negotiates a 500.0-m radius curve at 25.00 m/s. ... A car moving at 96.8 km/h travels around a circular curve of radius 182.9 m ... Because the car does not leave the surface of the road, the net vertical force ...

Explanation:

HE monda

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A wave along a guitar string has a frequency of 540 Hz and a wavelength of 4.3 m. Calculate the velocity of the wave.
Virty [35]

Answer:

Velocity of wave =  2322 m /sec

Explanation:

We know that, Velocity of wave v = n  λ

Given, n = 540 Hz,  λ=4.3 m , v = ?

Putting the value of n and λ

Velocity of wave = 540 x 4.3 = 2322 m /sec

8 0
3 years ago
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A 20 MHz carrier is frequency modulated by a sinusoidal signal such that the maximum frequency deviation is 100kHz. Calculate th
Ivan

Answer:

Idk

Explanation:

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3 years ago
A violin string is 45.0 cm long and has a mass of 0.242 g. When tightened on the neck of the violin, the distance between the pi
stiks02 [169]

Answer:

The tension is 75.22 Newtons

Explanation:

The velocity of a wave on a rope is:

v=\sqrt{\frac{TL}{M}} (1)

With T the tension, L the length of the string and M its mass.

Another more general expression for the velocity of a wave is the product of the wavelength (λ) and the frequency (f) of the wave:

v= \lambda f (2)

We can equate expression (1) and (2):

\sqrt{\frac{TL}{M}}=\lambda f

Solving for T

T= \frac{M(\lambda f)^2}{L} (3)

For this expression we already know M, f, and L. And indirectly we already know λ too. On a string fixed at its extremes we have standing waves ant the equation of the wavelength in function the number of the harmonic N_{harmonic} is:

\lambda_{harmonic}=\frac{2l}{N_{harmonic}}

It's is important to note that in our case L the length of the string is different from l the distance between the pin and fret to produce a Concert A, so for the first harmonic:

\lambda_{1}=\frac{2(0.425m)}{1}=0.85 m

We can now find T on (3) using all the values we have:

T= \frac{2.42\times10^{-3}(0.85* 440)^2}{0.45}

T=75.22 N

3 0
4 years ago
this stationary wave is what we call the first harmonic of the first normal mode of the system. in units of l, the length of the
Dafna1 [17]

The wavelength of the first harmonic of the standing wave is 2L.

<h3>What is a standing wave?</h3>

A standing wave is one in which the obvious points remain fixed as the vibration continues. A standing wave occurs in a wind instrument such as a trumpet, saxophone etc.

We know from  the formula of the first harmonic that the wavelength of the first harmonic of the standing wave is 2L.

Learn more about standing wave:brainly.com/question/1121886?

#SPJ11

3 0
2 years ago
Exercício:
zysi [14]

Answer:

a

Explanation:

a

a

a

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