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laiz [17]
2 years ago
8

A car, of mass 2.1 X 10^3 kg, travels in the horizontal plane around an unbanked curve of a radius of 275 m at a speed of 26 m/s

, without sliding.
a) Determine the minimum coefficient of static friction between the tires and the road.








b) How would your answer in part a) be affected if the mass of the vehicle were greater because of the presence of heavy cargo?





c) How would your answer in part a) be affected if the curve were sharper, i.e., if its radius were smaller?
Physics
1 answer:
Nadusha1986 [10]2 years ago
4 0

Answer:

Centripetal force is perpendicular to velocity and causes uniform circular motion. ... force exerted on a 900.0-kg car that negotiates a 500.0-m radius curve at 25.00 m/s. ... A car moving at 96.8 km/h travels around a circular curve of radius 182.9 m ... Because the car does not leave the surface of the road, the net vertical force ...

Explanation:

HE monda

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The force of attraction between the molecules of the same substance

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2 years ago
What is the total resistance in the circuit? (include unit in answer - ohms)
solmaris [256]

Answer:60 ohms

Explanation:

R1=30 ohms

R2=15 ohms

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4 0
3 years ago
A 75-kg sprinter accelerates from rest to a speed of 11.0 m/s in 5.0 s. (a) calculate the mechanical work done by the sprinter d
mezya [45]

The mechanical work done by the sprinter during this time will be 4537.5 J , the average power the sprinter must generate will be 907.5 W and if the sprinter converts food energy to mechanical energy with an efficiency of 25% then he will be burning calories at 54.20 calories per second.

Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. It is frequently described in its most basic form as the result of force and displacement.

The quantity of energy moved or transformed per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units.. A scalar quantity is power.

Given 75-kg sprinter accelerates from rest to a speed of 11.0 m/s in 5.0 s.

So let,

m = 75 kg

v = 11.0 m/s

t = 5.0 s

So the mechanical work done by the sprinter during this time will be as follow:

W = 0.5 mv²

W = 0.5 (75)(11)²

W = 4537.5 J

The average power the sprinter must generate will be as follow:

Power(P) = W / t

P =  4537.5/5

P = 907.5 W

Only 25% is absorbed. So, the sprinter only absorbed 226.875 J per second which is equal to 54.20 calories per second.

Hence   mechanical work done by the sprinter during this time will be 4537.5 J , the average power the sprinter must generate will be 907.5 W and if the sprinter converts food energy to mechanical energy with an efficiency of 25% then he will be burning calories at 54.20 calories per second.

Learn more about mechanical power here:

brainly.com/question/25573309

#SPJ10

8 0
1 year ago
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