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3 years ago

On what single factor does the efficiency of the Otto cycle depend?

Engineering

1 answer:

NNADVOKAT [17]3 years ago

4 0

Answer:

Compression ratio(r)

Explanation:

Otto cycle:

Otto cycle is an ideal cycle for all working petrol engine.It have four processes in which two are constant volume process and other two are reversible adiabatic or we can say that isentropic processes.All petrol engine works on Otto cycle.

The efficiency of Otto cycle given as follows

$\eta =1-\dfrac{1}{r^{\gamma-1}}$

Where r is the compression ratio and γ is heat capacity ratio.

So from above we can say that the efficiency of Otto cycle depends onl;y on compression ratio (r).

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Water is being added to a storage tank at the rate of 500 gal/min. Water also flows out of the bottom through a 2.0-in-inside di

melomori [17]

Answer:

From the answer, the water level is falling (since rate of outflow is more than that of inflow), and the rate at which the water level in the storage tank is falling is

(dh/dt) = - 0.000753

Units of m/s

Explanation:

Let the volume of the system at any time be V.

V = Ah

where A = Cross sectional Area of the storage tank, h = height of water level in the tank

Let the rate of flow of water into the tank be Fᵢ.

Take note that Fᵢ is given in the question as 500 gal/min = 0.0315 m³/s

Let the rate of flow of water out of the storage tank be simply F.

F is given in the form of (cross sectional area of outflow × velocity)

Cross sectional Area of outflow = πr²

r = 2 inches/2 = 1 inch = 0.0254 m

Cross sectional Area of outflow = πr² = π(0.0254)² = 0.00203 m²

velocity of outflow = 60 ft/s = 18.288 m/s

Rate of flow of water from the storage tank = 0.0203 × 18.288 = 0.0371 m³/s

We take an overall volumetric balance for the system

The rate of change of the system's volume = (Rate of flow of water into the storage tank) - (Rate of flow of water out of the storage tank)

(dV/dt) = Fᵢ - F

V = Ah (since A is constant)

dV/dt = (d/dt) (Ah) = A (dh/dt)

dV/dt = A (dh/dt) = Fᵢ - F

Divide through by A

dh/dt = (Fᵢ - F)/A

Fi = 0.0315 m³/s

F = 0.0371 m³/s

A = Cross sectional Area of the storage tank = πD²/4

D = 10 ft = 3.048 m

A = π(3.048)²/4 = 7.30 m²

(dh/dt) = (0.0315 - 0.0370)/7.3 = - 0.000753

(dh/dt) = - 0.000753

4 0

3 years ago

In which type of shoot is continuous lighting used?

Fiesta28 [93]

A type of shoot in which continuous lighting used is: 1) studio.

<h3>What is a photoshoot?</h3>

A photoshoot simply refers to a photography session which typically involves the use of digital media equipment such as a camera, to take series of pictures (photographs) of models, group, things or places, etc., especially by a professional photographer.

<h3>The types of shoot.</h3>

Basically, there are four main type of shoot and these include the following:

Studio

Underwater

Action

Landscape

In photography, a type of shoot in which continuous lighting used is studio because it enhances the photographs.

Read more on photography here: brainly.com/question/24582274

#SPJ1

4 0

2 years ago

Acertain foundation will experience a bearing capacity failurewhen it is subjected to a downward load of 2200 kN. Using ASD with

ehidna [41]

Answer:

Um...

Explanation:

This is what I like to see teachers giving out.

7 0

3 years ago

(Gas Mileage) Drivers are concerned with the mileage their automobiles get. One driver has kept track of several trips by record

Effectus [21]

Answer:

import java.util.*;

public class Main {

public static void main(String[] args) {

double milesPerGallon = 0;

int totalMiles = 0;

int totalGallons = 0;

double totalMPG = 0;

Scanner input = new Scanner(System.in);

while(true){

System.out.print("Enter the miles driven: ");

int miles = input.nextInt();

if(miles <= 0)

break;

else{

System.out.print("Enter the gallons used: ");

int gallons = input.nextInt();

totalMiles += miles;

totalGallons += gallons;

milesPerGallon = (double) miles/gallons;

totalMPG = (double) totalMiles / totalGallons;

System.out.printf("Miles per gallon for this trip is: %.1f\n", milesPerGallon);

System.out.printf("Total miles per gallon is: %.1f\n", totalMPG);

}

Explanation:

Initialize the variables

Create a while loop that iterates until the specified condition is met inside the loop

Inside the loop, ask the user to enter the miles. If the miles is less than or equal to 0, stop the loop. Otherwise, for each trip do the following: Ask the user to enter the gallons. Add the miles and gallons to totalMiles and totalGallons respectively. Calculate the milesPerGallon (divide miles by gallons). Calculate the totalMPG (divide totalMiles by totalGallons). Print the miles per gallon and total miles per gallon.

6 0

3 years ago

..........................

kow [346]

Answer:

i wish i knew what you meant by that

7 0

3 years ago