The correct answer is:
Atoms cannot be created or destroyed by chemical reactions.
the equation of the line allows us to find the answer is
y = -27.8 t + 97.4
The equation of a line in a linear relationship between two variables, its general expression is
y = A x + B
in this case the slope is the quantity that the independent variable in this case A = -27.8 m / s
The cut-off point that is the value of the dependent variable for x = is b = 97.4 m
In this case we see that the slope has a unit of [m / s] and the dependent variable is a unit of length, therefore the independent variable must have a unit of time [s] so that the entire equation is in units of length
y = -27.8 t + 97.4
[m] = [m / s] [s] + [m]
[m] = [m]
The other two magnitudes with are necessary to write the equation r is the mean square root and gives an idea that the values also fit the line, the best value is 1
In conclusion, the equation of the line allows us to find the answer is
y = -27.8 t + 97.4
learn more about the equation inear here:
brainly.com/question/22851869
Answer:
1.The temperature of each sample will increase by the same amount
Explanation:
This is because, since their specific heat capacities are the same and we have the same mass of each substance, and the same amount of energy due to heat flow is supplied to both the glass and brick at room temperature, their temperatures would thereby increase by the same amount.
This is shown by the calculation below
Q = mcΔT
ΔT = Q/mc where ΔT = temperature change, Q = amount of heat, m = mass of substance and c = specific heat capacity of substance.
Since Q, m and c are the same for both substances, thus ΔT will be the same.
So, the temperature of each sample will increase by the same amount
horizontal distance of home run is 400 ft = 122 m
height of the home run is 3 ft = 0.9 m
now the angle of the hit is 51 degree
now we have equation of trajectory of the motion


solving above two equations we have

now here we will plug in all data




<em>so the ball was hit with speed 35.1 m/s from the ground</em>