Provident fund Rs. 100.000,
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Answer:
The mass of the skateboard is 1.25 kg.
Explanation:
We have,
Mass of dog, m = 5 kg
Initial speed of dog, u = 2.5 m/s
Initial speed of skateboard, u' = 0 (at rest)
The dog jumps onto the skateboard and both the dog and skateboard move with a speed of 2.00 m/s. It is the common speed of the dog +skateboard, V = 2 m/s. We need to find the mass of the skateboard. Using conservation of momentum as :
m' is mass of skateboard
So, the mass of the skateboard is 1.25 kg.
The tension in the supporting cable when the cab originally moves downward is 18422.4 N
What is tension?
Tension is described as the pulling force by the means of a three-dimensional object.
Tension might also be described as the action-reaction pair of forces acting at each end of said elements.
Here,
m =combined mass = 1600 kg
s = Displacement of the elevator = 42 m
g = Acceleration due to gravity = 9.81 m/s²
u = Initial velocity = 12 m/s
v = Final velocity = 0
According to the equation of motion:
0 - 12^2 = 2*a*42
a = - 144 / 84
a = - 1.714 m/s^2
Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:
T-mg = ma
T = m(g-a)
T = 1600 ( 9.8-(-1.74))
T=18422.4 N
Hence,
The tension in the supporting cable when the cab, originally moving downward is 18422.4 N
Learn more about tension here:
<u>brainly.com/question/13772148</u>
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