Answer:A
Explanation: search for a gap in traffic and adjust your speed to the speed of the traffic.
Nitrogen fixing bacteria changes dead plants and animals into ammonia compounds.
<h2>What is nitrogen fixation?</h2>
Atmospheric nitrogen is converted into nitrogen oxides by the action of lightning, which helps its incorporation into the soil.
<h3>Characteristics of Nitrogen fixing bacteria</h3>
- Nitrogen is fixed by these bacteria and other prokaryotes through various metabolic processes, which convert it into different usable compounds, such as ammonia (NH3) and ammonium ion (NH4+).
- These microorganisms can be found in soil and water, or as plant symbionts.
Therefore, we can conclude that nitrogen fixing bacteria fix nitrogen from the air, that is, they originate soluble compounds by plants, such as ammonia.
Learn more about nitrogen fixation here: brainly.com/question/14726009
Answer:
It is longer
Explanation:
According to the theory of special relativity, moving clocks run slower. So, the construction worker moving at a constant speed observers a time much longer than the time I observe since I am stationary. If t is the time observed by me and v is the speed of the construction worker, then, the time observed by the construction worker, t' is given by
t' = t/√[1 - (v/c)²] where c = speed of light
So, the construction worker reports a longer time interval than me since his time runs slower.
Answer:
(a) Charge density σ=6.6375×10²nC/m²
(b) Total charge Q=1.47×10²nC
Explanation:
Given Data
A=47.0 cm =0.47 m
Electric field E=75.0 kN/C
To find
(a) Charge density σ
(b)Total Charge Q
Solution
For (a) charge density σ
From Gauss Law we know that
Φ=Q/ε₀.......eq(i)
Where
Φ is electric flux
Q is charge
ε₀ is permittivity of space
And from the definition of flux
Φ = EA
The flux is electric field passing perpendicularly through the surface
Put the this Φ in equation(i)
EA
=Q/ε₀
where Q(charge)=σA
EA=(σA)/ε₀
E=σ/ε₀
σ=ε₀E

σ=6.6375×10²nC/m²
For (b) total charge Q
Q=σA

Answer:
<h2>i. 9J and </h2><h2>ii. -9J</h2>
Explanation:
Please see attached the diagram and also the FBD for your reference.
Step one:
given data
Weight w1=20N
Distance s1=75cm= 0.75m
Weight w2=12N
Distance s2=75cm =0.75m
Clearly, we are asked to find the work done by gravity and the tension in the string.
we know that work is defined as force times the distance traveled
W=F*D
and to know the force we need the acceleration, seeing that the system is stationary the acceleration due to gravity 9.81m/s^2 is not needed here
i . Work done by gravity = w2*s2=12*0.75=9J
ii. The tension is equal but opposite = -9J