Answer:
![a=3125000 m/s^2\\a=3.125*10^6 m/s^2](https://tex.z-dn.net/?f=a%3D3125000%20m%2Fs%5E2%5C%5Ca%3D3.125%2A10%5E6%20m%2Fs%5E2)
Acceleration, in m/s, of such a rock fragment = ![3.125*10^6m/s^2](https://tex.z-dn.net/?f=3.125%2A10%5E6m%2Fs%5E2)
Explanation:
According to Newton's Third Equation of motion
![V_f^2-V_i^2=2as](https://tex.z-dn.net/?f=V_f%5E2-V_i%5E2%3D2as)
Where:
is the final velocity
is the initial velocity
a is the acceleration
s is the distance
In our case:
![V_f=V_{escape}, V_i=0,s=4 m](https://tex.z-dn.net/?f=V_f%3DV_%7Bescape%7D%2C%20%20V_i%3D0%2Cs%3D4%20m)
So Equation will become:
![V_{escape}^2-V_i^2=2as\\V_{escape}^2-0=2as\\V_{escape}^2=2as\\a=\frac{V_{escape}^2}{2s}\\a=\frac{(5*10^3m)^2}{2*4}\\a=3125000 m/s^2\\a=3.125*10^6 m/s^2](https://tex.z-dn.net/?f=V_%7Bescape%7D%5E2-V_i%5E2%3D2as%5C%5CV_%7Bescape%7D%5E2-0%3D2as%5C%5CV_%7Bescape%7D%5E2%3D2as%5C%5Ca%3D%5Cfrac%7BV_%7Bescape%7D%5E2%7D%7B2s%7D%5C%5Ca%3D%5Cfrac%7B%285%2A10%5E3m%29%5E2%7D%7B2%2A4%7D%5C%5Ca%3D3125000%20m%2Fs%5E2%5C%5Ca%3D3.125%2A10%5E6%20m%2Fs%5E2)
Acceleration, in m/s, of such a rock fragment = ![3.125*10^6m/s^2](https://tex.z-dn.net/?f=3.125%2A10%5E6m%2Fs%5E2)
Answer: A thin membrane.
Explanation:
When a sound signal is allowed to pass through the voice coil suspended between permanent magnet, magnetic field will be induced which will cause vibration in the diaphragm - a thin membrane causing disturbance of air in the surrounding of membranes which eventually produce sound waves.
Therefore, we can conclude that a thin membrane of the loud speaker produces sound waves
Just add all of them up and there is your answer I just added it but I want u to work it out to..
The force needed to accelerate a vehicle with a mass of 1000kg at a rate of 5m/s2 would be 5000