Answer:
The normal force N1 exerted by the floor is
The normal force N2 exerted by the wall is 
The frictional force exerted by the wall is
Explanation:
From the question we are told that
The length of the ladder is 
The weight of the ladder is
The distance of the ladder position on the wall from the floor is 
The mass of the person is 
Applying Pythagoras theorem
The length of the position the ladder on the ground from the base of the wall is

substituting values

In order the for the ladder not to shift from the ground the sum of the moment about the position of the ladder on the ground must be equal to zero this is mathematically represented as
![\sum M = 0 = N_2 * D - [\frac{1}{2} * W_L ] * [(mg) *A ]](https://tex.z-dn.net/?f=%5Csum%20M%20%3D%200%20%20%3D%20N_2%20%2A%20D%20-%20%5B%5Cfrac%7B1%7D%7B2%7D%20%2A%20W_L%20%5D%20%2A%20%5B%28mg%29%20%2AA%20%20%5D)
![\sum M = 0 = N_2 * 3.75 - [\frac{1}{2} * 69.0 ] * [(90*9.8) * \frac{4.6}{2.66} ]](https://tex.z-dn.net/?f=%5Csum%20M%20%3D%200%20%20%3D%20N_2%20%2A%203.75%20-%20%5B%5Cfrac%7B1%7D%7B2%7D%20%2A%2069.0%20%5D%20%2A%20%5B%2890%2A9.8%29%20%2A%20%5Cfrac%7B4.6%7D%7B2.66%7D%20%5D)



Now the force exerted by the floor on the ladder is mathematically represented as
substituting values
Now the horizontal forces acting on the ladder are
and they are in opposite direction so