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Nezavi [6.7K]
3 years ago
12

An extended period when temperatures are well below average is known as a/an

Physics
2 answers:
sasho [114]3 years ago
6 0
Depends on the "period". If weeks, months, or years, then it's a cold wave. If centuries, then you've got yourself an ice age.
Alecsey [184]3 years ago
3 0
It would be a cold wave. 
Ice ages occur when the temperatures are extremely cold.(long-term)  
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Which undergoes greater acceleration: an airplane that goes from 1000 km/h to 1005 km/h in 10 seconds or a skateboard that
Alex_Xolod [135]

Answer:

Skateboard

Explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

The airplane's acceleration is:

a = (1005 km/h − 1000 km/h) / 10 s

a = 0.5 km/h/s

The skateboard's acceleration is:

a = (5 km/h − 0 km/h) / 1 s

a = 5 km/h/s

6 0
3 years ago
Why is it that an object can accelerate while
posledela

For the same reason that you can skate around a curve at constant speed but not with constant velocity.

The DIRECTION you're going is part of your velocity, but it's not part of your speed.

If the DIRECTION changes, that's a change of velocity.

The object doesn't have to change speed to have a different velocity. A change of direction is enough to do it.

And any change of velocity is called acceleration.

3 0
3 years ago
Need some help with this!
zvonat [6]

Answer: what’s it asking

Explanation:

8 0
3 years ago
Read 2 more answers
If two planets orbit a star, but planet B is twice as far from the star as planet A, planet A will receive ____ times the flux t
Tresset [83]

Answer:

The nearest plant (A) receives 4 times more radiation from the farthest plant

Explanation:

The energy emitted by the star is distributed on the surface of a sphere, whereby intensity received is the power emitted between the area of ​​the sphere

                I = P / A

               P = I A

The area of ​​the sphere is

               A = 4π r²

Since the amount of radiation emitted by the star is constant, we can write this expression for the position of the two planets

               P = I₁ A₁ = I₂ A₂

               I₁ / I₂ = A₂ / A₁

 Suppose index 1 corresponds to the nearest planet,

            r2 = 2 r₁

            I₁ / I₂ = r₁² / r₂²

            I₁ / I₂ = r₁² / (2r₁)²

            I₁ / I₂ = ¼

           4 I₁ = I₂

The nearest plant (A) receives 4 times more radiation from the farthest plant

7 0
3 years ago
If this decay has half-life of 2 years, how many years would it take for 10.8 g Protactinium-231 to remain given an initial mass
sergij07 [2.7K]

Answer:

Time = 6 years

Explanation:

First, we will calculate the no. of half life periods required to reduce the mass of Protactinium to the given value:

m' = \frac{m}{2^{n} } \\\\2^n = \frac{m}{m'}

where,

n = no. of half-life periods = ?

m = initial mass = 86.3 g

m' = remaining mass = 10.8 g

Therefore,

2^n = \frac{86.3\ g}{10.8\ g}\\\\2^n = 8\\2^n = 2^3

Since the bases are the same. Therefore equating powers:

n = 3

Now we calculate the time:

Time = (n)(Half-Life)\\Time =(3)(2\ years)

<u>Time = 6 years</u>

3 0
3 years ago
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