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3 years ago

An extended period when temperatures are well below average is known as a/an

2 answers:

6 0

Depends on the "period". If weeks, months, or years, then it's a cold wave. If centuries, then you've got yourself an ice age.

Alecsey [184]3 years ago

3 0

It would be a cold wave.
Ice ages occur when the temperatures are extremely cold.(long-term)

You might be interested in

How do you divide 5 km by 2 hours?

aleksandr82 [10.1K]

5 km / 2 hrs

= (5/2) (km/hr)

= 2.5 km/hr .

7 0

3 years ago

A rifle bullet with mass 8.00 g and initial horizontal velocity 280 m/s strikes and embeds itself in a block with mass 0.992 kg

anyanavicka [17]

Answer:

0.4113772 s

Explanation:

Given the following :

Mass of bullet (m1) = 8g = 0.008kg

Initial horizontal Velocity (u1) = 280m/s

Mass of block (m2) = 0.992kg

Maxumum distance (x) = 15cm = 0.15m

Recall;

Period (T) = 2π√(m/k)

According to the law of conservation of momentum : (inelastic Collison)

m1 * u1 = (m1 + m2) * v

Where v is the final Velocity of the colliding bodies

0.008 * 280 = (0.008 + 0.992) * v

2.24 = 1 * v

v = 2.24m/s

K. E = P. E

K. E = 0.5mv^2

P.E = 0.5kx^2

0.5(0.992 + 0.008)*2.24^2 = 0.5*k*(0.15)^2

0.5*1*5.0176 = 0.5*k*0.0225

2.5088 = 0.01125k

k = 2.5088 / 0.01125

k = 223.00444 N/m

Therefore,

Period (T) = 2π√(m/k)

T = 2π√(0.992+0.008) / 233.0444

T = 2π√0.0042910

T = 2π * 0.0655059

T = 0.4113772 s

6 0

3 years ago

For a given centrifugal pump, if the speed of rotation of the impeller is cut in half, how does the power required to drive the

Andru [333]

Answer:

The power required to drive the pump is reduced in $\frac{1}{8}$ .

Explanation:

From Turbomachinery, we find that power required to drive the pump ( $\dot W$ ) is directly proportional to the cube of the speed of rotation of the impeller ( $\dot n$ ). That is:

$\dot W \propto \dot n^{3}$

$\dot W = k\cdot \dot n ^{3}$ (Eq. 1)

Where $k$ is the proportionality constant.

And now we eliminate the proportionality constant by constructing the following relationship:

$\frac{\dot W_{B}}{\dot W_{A}} = \left(\frac{\dot n_{B}}{\dot n_{A}}\right)^{3}$ (Eq. 2)

If we know that $\frac{\dot n_{B}}{\dot n_{A}} = \frac{1}{2}$ , then:

$\frac{\dot W_{B}}{\dot W_{A}} = \frac{1}{8}$

The power required to drive the pump is reduced in $\frac{1}{8}$ .

4 0

3 years ago

Develop an equation (with a proportionality constant) that describes the relationship between the gravitational force (fgrav), t

ivolga24 [154]

According to newton's law of gravitation, the gravitational force(F) is directly proportional to the product mass of the moon(Mm) and the mass of the planet (Mp) and it is inversely proportional to the square of the separation between them.

Fg ∝ (Mp)(Mm) →(1)

Fg ∝ 1/d²→(2)

Combining equation (1) and (2),

Fg ∝ (Mp)(Mm)/d²

Fg = G(Mp)(Mm)/d²

This is an equation that describes the relation between mass of moon (Mm) and mass of planet (Mp) and separation(d) between them.

To support the claim in favuor of this equation we use this equation to obtain the value of acceleration due to gravity on earth.

Let m be the mass of an object on earth then Fg between earth (Mp) and mass of an object is obtained by:

Fg = G(Mp)(m)/R², where R= Radius of earth

This force is equal to the weight of an object i.e.,

g= G(Mp)/R²

Putting the values of G, Mp and R , we get, g=9.81 m/s²

which is the value we obtained on earth for acceleration due to gravity.

To know more about gravitational constant, visit:

brainly.com/question/13959861

#SPJ4

5 0

1 year ago

A student walks 5.00 m at an angle of 53.0° then walks another 8.00 m at angle of 130°. what is the magnitude of the student's f

dmitriy555 [2]

This question can easily be answered using a scientific calculator via complex mode using the form r∠α wherein r is the magnitude and α is the angle. So, incorporating vector addition through scientific calculator:

5∠53° + 8∠130 = 10.34∠101.9°

Therefore, the student's displacement is 10.34 m, 101.9°. In other words, the student is heading 78.1° (180 - 101.9 = 78.1) south of east.

6 0

4 years ago

Read 2 more answers