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asambeis [7]
3 years ago
11

If the voltage across a circuit of constant resistance is doubled, the power dissipated by that circuit will

Physics
1 answer:
densk [106]3 years ago
6 0

Answer:

The voltage will quadruple

Explanation:

The power dissipated in a circuit is given by

P=\frac{V^2}{R}

where

V is the voltage

R is the resistance

In this problem, the voltage across the circuit is doubled:

V' = 2V

So the new power dissipated is

P'=\frac{V'^2}{R}=\frac{(2V)^2}{R}=4\frac{V^2}{R}=4 P

so, the power dissipated will quadruple.

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