Given:
35.0 mL of acid with an unknown concentration
24.6 mL of 0.432 M base
Required:
Concentration of the acid
Solution:
M1V1 = M2V2
M1 (35.0 mL of acid)
= (0.432 M base) (24.6 mL
of base)
V1 = (0.432
M base) (24.6 mL of base) /
(35.0 mL of acid)
M1 = 0.304 M of acid
A i believe is the answer
Answer:
2.77532244 grams
Explanation:
Percent yeild=actual/theoretical * 100
Plug in the values
93.4452=actual/2.97 *100
0.934452*2.97=2.77532244
Hey there : !
density = 10.5 g/cm³
volume = 23.6 cm³
therefore:
D = m / V
10.5 = m / 23.6
m = 10.5 * 23.6
m = 247.8 g
hope this helps!
We have a 3-colour vision which happens to be the primary colours: red, blue and yellow. So, we can see red, and that is why we see it.
To see other we just mix the different cells as if we where mixing paint to get a new colour.
Hope it was easy to understand,
Happy homework/ study/ exam!
