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nikitadnepr [17]
4 years ago
11

The advantages of solar cells include all of the following, except a.moderate net energy yield b.little or no direct emissions o

f carbon dioxide c.electricity storage systems readily available d.easy to install and expand as needed epetitive costs for newer cells
Engineering
1 answer:
Xelga [282]4 years ago
6 0

Answer:

C

Explanation:

One of the disadvantages of solar cells is that electricity storage systems are not readily available. Excess energy generated by the solar panels are wasted except they are stored by solar batteries for later use. There are various systems for storing electricity from solar cells apart from solar batteries which is the common storage system. An example of another electricity storage system for solar cell is using the water electrolyzer to store solar energy which can be used to later generate hydroelectricity.

Advantages of a solar cell includes Renewable energy, Economy-friendly and environmental-friendly energy and good durability

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A solid cylinder is concentric with a straight pipe. The cylinder is 0.5 m long and has an outside diameter of 8 cm. The pipe ha
poizon [28]

Answer :  

The force needed to move the cylinder is 25.6 N

<h2>Further explanation  </h2>

Given that,  

Length of the cylinder, l = 0.5 m  

Outer diameter of the cylinder, d = 8 cm = 0.08 m  

Outer radius of the cylinder, r=0.04\ m  

Inside diameter of the pipe, d = 8.5 cm = 0.085 m  

Inside radius of the pipe, r=0.0425\ m  

Specific gravity of the oil, \rho=0.92  

Density of oil, d=\rho\times \rho_w

Kinematic viscosity of the oil, v=5.57\times 10^{-4}\ m^2/s  

Velocity of the cylinder, u = 1 m/s  

We need to find the force needed to move the cylinder. Let the force is F.  

Specific gravity is defined as the ratio of the density of the substance to the density of water.  

Kinematic viscosity is the acquired resistance of a fluid when there is no external force is acting except gravity. It is denoted by v.

Absolute viscosity is given by :

v=\dfrac{\mu}{d}

Where, d = density of oil

And d=\rho\times \rho_w (density of oil = specific gravity × density of water )

d=0.92\times 10^3\ kg/m^3

So,  

\mu=v\times d..............(1)

\mu=5.57\times 10^{-4}\ m^2/s\times 0.92\times 10^3\ kg/m^3

\mu=0.512\ Pa-s

The separation between the cylinder and pipe is given by :

dy=\dfrac{d_p-d_c}{2}=\dfrac{8.5-8}{2}=0.25\ cm=0.0025\ m

d_p\ and\ d_c are diameter of pipe and cylinder respectively.  

The mathematical expression for the Newton's law of viscosity can be written as:  

\tau\propto\dfrac{du}{dy}  

\tau=\mu\times \dfrac{du}{dy}..........(2)  

Where  

\tau = Shear stress, \tau=\dfrac{F}{A}............(3)  

\mu = viscosity  

\dfrac{du}{dy} = rate of shear deformation

On rearranging equation (1), (2) and (3) we get :  

\dfrac{F}{A}=v\times \rho\times \dfrac{du}{dy}...............(4)  

A is the area of the cylinder, A=2\pi rl  

Equation (4) becomes :  

F=v\times \rho\times \dfrac{du}{dy}\times 2\pi rl..............(5)

A=\pi d\times l

A=\pi \times 0.08\ m\times 0.5\ m

A=0.125\ m^2

Now, equation (5) becomes :

F=(v\times \rho)\times \dfrac{du}{dy}\times 2\pi rl

F=(0.512\ Pa-s)\times (\dfrac{1}{0.0025\ m})\times \times 0.125\ m^2

F = 25.6 N

<h2>Learn more  </h2>

Kinematic viscosity : brainly.com/question/12947932

<h2>Keyword :  </h2>

Specific gravity, Kinematic viscosity, Area of cylinder, fluid mass density.  

7 0
3 years ago
Refrigerant-134a is to be cooled by water in a condenser. The refrigerant enters
KonstantinChe [14]

Answer:

Refrigerant R-134a is to be cooled by waterin a condenser.The refrigerant enters thecondenser with a mass flow rate of 6 kg/minat 1 MPa and 70 C and exits at 35 C. The cool-ing water enters at 300 kPa and 15 C andleaves at 25 C. Neglecting pressure drops,determine a) the required mass flow rate ofthe cooling water, and b) the heat transferrate from the refrigerant to the water.SolutionFirst consider the condenser as the control volume. The process is steady,adiabatic and no work is done. Thus over any time intervalΔt,ΔEΔt=0and thusXin˙E=Xout˙Ewhere˙E=˙m h+12V2+gz650:351 Thermodynamics·Prof. Doyle Knight37

Background image

I only know this

sorry for errors

4 0
3 years ago
Help me pls with tools
irina1246 [14]

Answer:

How?

Explanation:

3 0
4 years ago
Read 2 more answers
Air enters a compressor at 100 kPa and 25 ⁰C. It is compressed to 2 MPa and exits the compressor at 540 K. The compressor is at
AysviL [449]

Answer:

(a) The reversible work is 207 kJ/kg

(b) The irreversibility rate is -38.39 kJ/kg

Explanation:

State1 : p1 = 100kpa, T1= 25+273 =298k

From air table, h1 =298.18 kJ/kg, s10= 1.69528 kJ/kgK

State 2a:p2=2mpa,t2=540k (actual condition 2a)

h2a= 544.35 kJ/kg,s2a0=2.29906

actual work input to the compressor =wout=h1-h2+Qin

=298.18-544.35+(-150)kJ/kg(- sign indicate heat loss)

=(-246.17)kJ/kg(-ve sign indicates the work is given into the system

a) Reversible work= Win actual - any irreversiblities present

                             =246.17 + irreversibilty

b) irreversibility = T0(Entopy generation Sgen) for air, Sgen

                         =s20-s10-Rln(p2/p1), T0=250C

                         =(25+273)(s2a0-s10-Rlnp2/p1+Qout/Tsurr)

    = 298x[(2.29906-1.69528-0.287kJ/kgK xln(2000kpa/100) + 150 /298]

  = -38.39 kJ/kg

a)Reversible work = Win actual -any irreversiblities present                  

                           =246.17 + irreversibilty

                           =246.17+-38.39

                          =207 kJ/kg

8 0
3 years ago
What is the short description for Determining Deflections by Using Discontinuity Functions ?
maksim [4K]

Answer? somey

Explanation:

soy sause

6 0
3 years ago
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