Answer:

Explanation:
Hello!
In this case, we compute the heat output from coal, given its heating value and the mass flow:

Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:

Best regards!
Answer:
Condition A
Heat flux is 1400 W/M^2
Condition B
Heat flux is 12800 w/m^2
Explanation:
Given that:
is given as 30 degree celcius
condition A
Air temperature = - 5 degree c
convection coefficient h = 40 w/m^2. k

condition A
water temperature = 10 degree c
convection coefficient = 800 w/m^2.k

Answer:
Professional engineering license
Bachelor's degree
Computer science classes
job recommendations
Ehheem✔️
Explanation:
✔️✖️✔️✖️✔️✖️