Answer:
hello some parts of your question is missing attached below is the missing part ( the required fig and table )
answer : The solar collector surface area = 7133 m^2
Explanation:
Given data :
Rate of energy input to the collectors from solar radiation = 0.3 kW/m^2
percentage of solar power absorbed by refrigerant = 60%
Determine the solar collector surface area
The solar collector surface area = 7133 m^2
attached below is a detailed solution of the problem
Answer:
the rate of heat loss by convection across the air space = 82.53 W
Explanation:
The film temperature
to kelvin = (5 + 273)K = 278 K
From the " thermophysical properties of gases at atmospheric pressure" table; At = 278 K ; by interpolation; we have the following
→ v 13.93 (10⁻⁶) m²/s
→ k = 0.0245 W/m.K
→ ∝ = 19.6(10⁻⁶)m²/s
→ Pr = 0.713
The Rayleigh number for vertical cavity
=
=
For the rectangular cavity enclosure , the Nusselt number empirical correlation:
h = 1.99 W/m².K
Finally; the rate of heat loss by convection across the air space;
q = hA(T₁ - T₂)
q = 1.99(1.4*0.96)(20-(-10))
q = 82.53 W
Answer:
load factor = 0.782
Shrink Factor = 0.833
no of truck is 62500
Explanation:
given data
soil weighs in situ condition = 2,520 lbs/CY
soil weighs in loose condition = 1,970 lb/CY
soil weighs in embanked state = 3,025 lbs/CY
average volume = 16 LCY
soil from a borrow pit = 1 million CCY
solution
first we get here Load Factor that is express as
load factor =
load factor = 0.782
and Shrink Factor will be as
Shrink Factor =
Shrink Factor = 0.833
and
no of truck will be
no of truck =
no of truck is 62500