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3 years ago

The production of an electric current by a changing magnetic field is known as

Physics

2 answers:

Lorico [155]3 years ago

8 0

I believe its 'magnetic induction' or 'electromagnetic induction'

Maru [420]3 years ago

3 0

Answer:

electromagnetic induction

Explanation:

just now I did it and it came out right

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You pull your little sister across a flat snowy field on a sled. Your sister plus the sled have a mass of 25 kg. The rope is at

erik [133]

Answer

Work done will be equal to 1229.296 J

Explanation:

We have given mass of the sister m = 25 kg

Angle between rope and ground $\Theta =38^{\circ}$

Force F = 30 N

So horizontal force $=Fcos\Theta =30\times cos38^{\circ}=23.64N$

Distance traveled d = 52 m

'We have to find the wok done

Work done is equal to multiplication of horizontal force and distance

So work done $W=23.64\times 52=1229.296J$

7 0

3 years ago

If a driver is tired, the thinking distance will be less. True or false.why?

Evgesh-ka [11]

Answer:

False

Explanation:

When a driver is impaired the brain will need an extra second or two to wake up, after it does wake up it tends to drift off regularly.

8 0

4 years ago

A mass is stretched 4 centimeters from the equilibrium position of a spring. If the displacement is doubled, what can be conclud

marta [7]

From Simple Harmonic Motion (SHM), the restoring force is given by:

F = -ω²x

We can see that restoring force is proportional to the displacement, x. So if the displacement x is doubled, then the restoring force will also be doubled.

8 0

3 years ago

Read 2 more answers

A nonconducting ring with a radius of 11.5 cm is uniformly charged with a total positive charge of 10.0 µC. The ring rotates at

zhuklara [117]

Answer:

$B=1.21*10^{-10}T$

Explanation:

The magnitude of the magnetic field on the axis of the ring is given by:

$B=\frac{\mu_0 IR^2}{2(r^2+R^2)^{\frac{3}{2}}}(1)$

$\mu_0$ is the permeability of free space, $I$ is the flowing current through the ring, $R$ is the ring's radius and $r$ is the distance to the center of the ring.

The flowing current through the ring is defined as the ring's charge divided into the time taken by the charge to complete one revolution, that is, the period $T=\frac{2\pi}{\omega}$ . So, we have:

$I=\frac{q}{T}\\I=\frac{q}{\frac{2\pi}{\omega}}\\\\I=\frac{\omega q}{2\pi}\\I=\frac{18\frac{rad}{s}(10*10^{-6}C)}{2\pi}\\I=2.87*10^{-5}A$

Now, replacing in (1):

$B=\frac{(4\pi*10^{-7}\frac{T\cdot m}{A})(2.87*10^{-5}A)(0.115m)^2}{2((0.05m)^2+(0.115m)^2)^{\frac{3}{2}}}\\B=1.21*10^{-10}T$

6 0

4 years ago

During a football game, a receiver has just caught a pass and is standing still. Before he can move, a tackler, running at a vel

Nata [24]

Answer:

133 kg

Explanation:

Parameters given:

Mass of tackler, m = 133 kg

Initial velocity of tackler, u = 3.4 m/s

Final velocity of tackler and receiver, v = 1.7 m/s

Since momentum is conserved, we apply the principle of conservation of momentum:

Total initial momentum = Total final momentum

mu + MU = (m + M)v

Where U = initial velocity of receiver = 0 m/s

M = mass of receiver

Therefore:

(133 * 3.4) + (M * 0) = (133 + M) * 1.7

452.2 = (133 + M) * 1.7

(133 + M) = 452.2/1.7

133 + M = 266

=> M = 266 - 133

M = 133 kg

The mass of the receiver is 133 kg.

4 0

4 years ago