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yaroslaw [1]
3 years ago
12

Two negative charges are both -3.0C push each other apart with a force of 19.2N. How far apart are the two charges?

Physics
1 answer:
Lilit [14]3 years ago
5 0

06758 m

Explanation:

it is correct because that is what

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Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
kumpel [21]

Answer:\frac{D_A}{v_B-v_A}

Explanation:

Given

car A had a head start of D_A

and it starts at x=0 and t=0

Car B has to travel a distance of D_A and d_a

where d_a is the distance travel by car A in time t

distance travel by car A is

d_a=v_A\times t

For car B with  speed v_B

d_B=D_A+d_a

v_B\times t=D_A+v_A\times t

t=\frac{D_A}{v_B-v_A}

7 0
4 years ago
The direction of the magnetic field produced by an electric current will change when the direction of the ______changes.
Vinvika [58]

Answer: Electric current

Explanation: The direction of the magnetic field produced by an electric current will change when the direction of the electric current changes.

5 0
3 years ago
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How far is the sun away from earth
lisabon 2012 [21]

Answer:

The Sun is at an average distance of about 93,000,000 miles (150 million kilometers) away from Earth. It is so far away that light from the Sun, traveling at a speed of 186,000 miles (300,000 kilometers) per second, takes about 8 minutes to reach us.

Explanation:

8 0
3 years ago
A boy whirls a ball on a string 1.0 m long in a horizontal circle at 50 rpm. If the mass of the ball is 0.22 kg
vazorg [7]

Hi there! :)

We can begin by doing a summation of forces on the ball. In the horizontal direction, we have the force of tension:
F_{Net} = T

The tension force results in a centripetal force experienced by the ball. The equation of centripetal force is equivalent to:
F_C = m\omega^2 r

F_C = Centripetal force (N)
m = mass of ball (0.22 kg)

ω = angular speed of ball(? rad/sec, must convert rpm to rad/sec)

r = radius/length of string (1.0 m)

We must begin by converting rpm to rad/sec:

\frac{50 rev}{min} * \frac{2\pi rad}{1 rev}* \frac{1 min}{60 sec} = 5.236 \frac{rad}{s}

Now, we can set tension equal to the centripetal force and solve. T = F_{Net} = F_C\\\\T = m\omega^2 r\\\\T = (0.22)(5.236^2)(1) = \boxed{6.031 N}

6 0
2 years ago
A positron with kinetic energy 2.30 keV is projected into a uniform magnetic field of magnitude 0.0980 T, with its velocity vect
Mama L [17]

Answer:

a)0.364 ns

b)1.43 x 10^-3

c)163.21 x 10^-5 m

Explanation:

mass of the positron is m=9.1 x 10^-31 kg

charge is q=1.6 x 10^-19 C

strength of the magnetic field is B=0.0980 T

kinetic energy is K=2.30 keV=2.30 x 10^3 x 1.6 x 10^-19 J

0.5mv^2=6.68 x 10^-16 J

0.5 x 9.1 x 10^-31 x v^2 =3.68 x 10^-16

v=2.84 x 10^7 m/s

a)the period is T=2πm/qB

                         =2π(9.1 x 10^-31 )/1.6 x 10^-19x 0.0980

                         =0.364 ns

b) pitch is p=vcosθ(2πm/qB)

                  =2.84 x 10^7x cos82(0.364 x 10^-9)

                  =1.43 x 10^-3

c) radius is r=mvsinθ/qB

                  =(9.1 x 10^-31 )2.84 x 10^7x sin82/1.6 x 10^-19x 0.098

                   =163.21 x 10^-5 m

3 0
4 years ago
Read 2 more answers
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