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kvasek [131]
3 years ago
13

Valerie wants to examine the properties of a thick liquid but is finding it difficult to pour the liquid into a beaker. she need

s to finish her investigation before the end of class. which method will allow her to pour the liquid easily?
a. boiling the liquid vigorously
b. applying heat to the liquid
c. placing the liquid in the refrigerator
d. mixing the liquid with another solution
Chemistry
1 answer:
AlladinOne [14]3 years ago
5 0
B applying heat to the liquid
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17.42 mL of 0.1M NaOH was needed to reach the endpoint in the titration. How many moles of NaOH are in 17.42 mL of 0.1M NaOH
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Answer:

0.001742moles

Explanation:

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I know how to solve it with D=M/V and M1V1 however the answer isn’t correct. Help me please
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Answer:

23.28 g of O2.

Explanation:

We'll begin by calculating the mass of hexane. This can obtain as follow:

Volume of hexane = 10 mL

Density of hexane = 0.66 g/mL

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Density = mass /volume

0.66 = mass of hexane /10

Cross multiply

Mass of hexane = 0.66 x 10

Mass of hexane = 6.6 g

Next, we shall write the balanced equation for the reaction. This is given below:

2C6H14 + 19O2 —> 12CO2 + 14H2O

Next, we shall determine the masses of C6H14 and O2 that reacted from the balanced equation. This can be obtained as follow:

Molar mass of C6H14 = (12.01x6) + (1.008 x 14)

= 72.06 + 14.112

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Mass of C6H14 from the balanced equation = 2 x 86.172 = 172.344 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 19 x 32 = 608 g

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Finally, we shall determine the mass of O2 needed to react with 10 mL (i.e 6.6 g) of hexane, C6H14. This can be obtained as follow:

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Therefore, 6.6 g of C6H14 will react with = (6.6 x 608)/172.344 = 23.28 g of O2.

Therefore, 23.28 g of O2 is needed for the reaction.

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Answer:

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