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3 years ago

Choose "extinct" if the species is extinct and "endangered" if the species is endangered.

Physics

2 answers:

Dovator [93]3 years ago

8 0

Answer:

B.endangered

Explanation:

Choose "extinct" if the species is extinct and "endangered" if the species is endangered.

Sixty years ago, as few as 20 whooping cranes were left on earth. Now, thanks to conservation efforts, there are more than 300 whooping cranes in the wild.

A.extinct

B.endangered

if there are 20 whooping cranes sixty years ago, and then we have more than 300 today. then it means that the species are endangered

I will go with B

An extinct species no longer exist because there are no offsprings of the parent specie which can give birth to more subspecies .

species no longer exist anywhere on Earth, and once gone they are gone ... on International Trade In Endangered Species like Wild Fauna and Flora (CITES). .... in 1975; the species now numbers more than 1, 000 animals .... whooping cranes, this approach fails to protect most endangered species

Endangered means that the existence is threatened by some human activities, prevailing conditions in the environment or the host it feeds on to survive no longer exists within it reach, hence its survival is at stake

ohaa [14]3 years ago

7 0

The species is actually endangered and not extinct because there are only 20 species left. Extinct actually means that there would be no species left and so it an incorrect option. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer has helped you.

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2 years ago

A hard-boiled egg of mass 46.0 gg moves on the end of a spring with force constant 25.6 N/mN/m . The egg is released from rest a

soldi70 [24.7K]

Answer:

0.022kg/s

Explanation:

We are given that

Mass of boiled egg=46 g= $\frac{46}{1000} kg=0.046 kg$

$1kg=1000 g$

Constant force=F=25.6 N/m

Initial displacement= $A_1=0.296 m$

Final displacement= $A_2=0.12 m$

Time=t=4.55 s

Damping force= $F_x=-bv_x$

We have to find the magnitude of damping constant b.

We know that the displacement of the oscillator under damping motion is given by

$x=Ae^{-\frac{b}{2m}t}cos(w't+\phi)$

For maximum displacement $cos(w't+\phi)=1$

Therefore , $x=A_2$

Substitute the values

$A_2=A_1e^{-\frac{-b}{2m}t}$

$e^{-\frac{b}{2m}t}=\frac{A_2}{A_1}$

$-\frac{b}{2m}t=ln\frac{A_2}{A_1}$

$lnx=y\implies x=e^y$

Substitute the values

$-\frac{b}{2\times 0.046}\times 4.55=ln\frac{0.12}{0.296}$

$\frac{2\times 0.046}{4.55b}=ln\frac{0.296}{0.12}$

$\frac{2\times 0.046}{4.55}=0.9b$

$b=\frac{2\times 0.46}{4.55\times 0.9}=0.022kg/s$

Hence,the magnitude of damping constant b=0.022kg/s

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2 years ago

A block is held at rest against a wall by a force of magnitude F exerted at an angle theta from the horizontal, as shown in the

wel

Answers:

B.) $F cos\theta=F_{n}$

C.) $F sin\theta=F_{g} \pm F_{f}$

Explanation:

The image attached shows the way the force $F$ is acting on the block. Now, if we draw a free body diagram of the situation and write the equations for the Net Force in X and Y, we will have the following: