Because its just enough to where its not out f the gravitational pull and not close enough to be pulled back to earth. Hope it helps<span />
Answer:
The velocity is 31.25 m/s and direction is toward west.
Explanation:
Given that,
Distance 
Magnetic field 
Mass of proton 
Radius of earth 
Radius of orbit 


We need to calculate the speed
Using formula of magnetic field


Put the value into the formula


Hence, The velocity is 31.25 m/s and direction is toward west.
F = ma
We have mass = 0.2kg
and acceleration = 20 m/s^2
So..
F = (0.2)(20)
F = 4 N