Chicago uses 1.2x10^9 gallons of water/day.How many gallons per second must be pumped from the adjacent Lake Michigan every seco
2 answers:
Answer:
13,888.88 gallons per second must be pumped from the adjacent Lake Michigan every second to supply the city.
Explanation:
Gallons of water used by Chicago city in 1 day =
1 day = 24 hours
1 hour = 60 mins
1 min = 60 seconds
Gallons of water used by Chicago city in 86,400 seconds :
=
Gallons of water used by Chicago city in 1 second:
13,888.88 gallons per second must be pumped from the adjacent Lake Michigan every second to supply the city.
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Answer: a. solution
Explanation:
A solution is a mixture which contains two or more than two types of components and they can be separated by physical means as well.Example: salt water
Molecule of an element is defined as the aggregate of atoms of similar elements. Example: . Molecule of a compound is the aggregate of atoms of different elements in a fixed ratio by mass. Example:
Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example:
A pure substance is a substance which contains definite composition of only one type of component. Hence, it cannot be separated by physical means. Example: Helium, water
Answer:
Compound B.
Explanation:
The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.
where b is the molal concentration
If m is constant (5 g), then
The compound with the greater molar mass has fewer moles and therefore fewer particles to depress the freezing point.
That must be Compound B, because Compound A has the lower freezing point.
This is an incomplete question, here is a complete question.
Calculate the volume in milliliters of a 1.29 mol/L iron(II) bromide solution that contains 275 mmol of iron(II) bromide . Round your answer to significant 3 digits.
Answer : The volume of iron(II) bromide solution is,
Explanation : Given,
Concentration of iron(II) bromide = 1.29 mo/L
Moles of iron(II) bromide = 275 mmol = 0.275 mol
conversion used : 1 mmol = 0.001 mol
Now we have to calculate the volume of iron(II) bromide.
Now put all the given values in this formula, we get:
Thus, the volume of iron(II) bromide solution is,