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TEA [102]
3 years ago
6

Chicago uses 1.2x10^9 gallons of water/day.How many gallons per second must be pumped from the adjacent Lake Michigan every seco

nd to supply the city?
Chemistry
2 answers:
Rzqust [24]3 years ago
8 0

13888.8888889 i think?

ira [324]3 years ago
7 0

Answer:

13,888.88 gallons per second must be pumped from the adjacent Lake Michigan every second to supply the city.

Explanation:

Gallons of water used by Chicago city in 1 day = 1.2\times 10^9 gal

1 day = 24 hours

1 hour = 60 mins

1 min = 60 seconds

1 day=24\times 60\times 60 min = 86,400 seconds

Gallons of water used by Chicago city in 86,400 seconds :

= 1.2\times 10^9 gal

Gallons of water used by Chicago city in 1 second:

\frac{1.2\times 10^9 gal}{86,400}=13,888.88 gal

13,888.88 gallons per second must be pumped from the adjacent Lake Michigan every second to supply the city.

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Ostrovityanka [42]
I believe it is 32.3g, I apologize if it is wrong!
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2 years ago
A gas occupies 25.3 at pressure of 790.5 mmHg. Determine the volume if the pressure is reduced to 8.04 mmHg
taurus [48]

Answer:

2487.51.

Explanation:

As per Boyle's law temperature remaining constant the volume of an ideal gas is inversely proportional to its pressure.

pV= k

therefore, p1V1 = p2V2

here V1 = 25.3, p2 = 8.04mm Hg

pressure p1 = 790.5 mm Hg

this means that

25.3×790.5 = 8.04V2

⇒V2= 2487.51

Hence, the required volume is, 2487.51.

5 0
2 years ago
How does your pattern of breathing change when you exercise and then rest ?​
Paladinen [302]

Your pattern of breathing increases, making it faster than usual, when you're exercising because you're pushing your body to work harder and speeding up your heart rate making you tired.

When you're resting your breathing pattern should be steady and normal since you aren't doing anything that requires lots of body work or something that would make you out of breath.

Hope this helps,

Davinia.

7 0
3 years ago
What is the percent composition of CuO if a sample of CuO with a mass of 62.5 g contains 12.5 g of oxygen (O) and 50 g of Cu
Arlecino [84]

Percent (%) Composition of CuO

Cu = 1 x 50g      - Multiply by one as there is one Cu

O = 1 x 12.5g      - Multiply by one as there is one O

CuO = 62.5g

% for Cu = 50g over 62.5 multiplied by 100 = 80%

% for O = 12.5g over 62.5 multiplied by 100 = 20%

Final Answer :

<em>Percent (%) Composition of CuO = </em>80% (Cu) & 20% (O)

7 0
3 years ago
g Calculate the [OH-] from the results of your titrations. Explain your calculations2. Calculate the [Ca2+]. Explain your calcul
RideAnS [48]

Answer:

Explanation:

*Since the titration is between the strong acid HCl and the strong base Ca(OH)2, the pH at the equivalent point should be 7. On interpolation, we will obtain that 9.50mL and 9.82 mL of HCl is required to completely neutralized the given Ca(OH)2 solution.

*pH at the equivalence point =7

we know that pH + pOH = 14

Hence pOH= 14-7=7

pOH= -log(OH-)

The concentration of OH-= 10-pH= 1X10-7 M

One reason for the low solubility may be the higher reaction temperature, Another reason is the common ion effect.

3 0
3 years ago
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