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TEA [102]
3 years ago
6

Chicago uses 1.2x10^9 gallons of water/day.How many gallons per second must be pumped from the adjacent Lake Michigan every seco

nd to supply the city?
Chemistry
2 answers:
Rzqust [24]3 years ago
8 0

13888.8888889 i think?

ira [324]3 years ago
7 0

Answer:

13,888.88 gallons per second must be pumped from the adjacent Lake Michigan every second to supply the city.

Explanation:

Gallons of water used by Chicago city in 1 day = 1.2\times 10^9 gal

1 day = 24 hours

1 hour = 60 mins

1 min = 60 seconds

1 day=24\times 60\times 60 min = 86,400 seconds

Gallons of water used by Chicago city in 86,400 seconds :

= 1.2\times 10^9 gal

Gallons of water used by Chicago city in 1 second:

\frac{1.2\times 10^9 gal}{86,400}=13,888.88 gal

13,888.88 gallons per second must be pumped from the adjacent Lake Michigan every second to supply the city.

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The majority of the elements essential to life are found in what part of the periodic table?
IRINA_888 [86]
The rows in the top third - This group consists of elements like Sodium, Magnesium, Potassium and Calcium on the right and Chlorine, Carbon, Nitrogen and Oxygen on the left.
Sodium and Chlorine are components of salt, a very important compound of our blood, essential for transferring electrical signals from the brain to the rest of the body and vice versa. Calcium is the building block of our bones, while Magnesium and potassium ensure proper functioning of our organs.

3 0
3 years ago
What is the molarity of a solution that is made by mixing 35.5 g of Ba(OH)2 in 325 ml of solution?
choli [55]

Answer:

M=0.638M

Explanation:

Hello!

In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:

n=35.5g Ba(OH)_2*\frac{1molBa(OH)_2}{171.34gBa(OH)_2}\\\\n=0.207mol

Then, the liters of solution:

V=325mL*\frac{1L}{1000mL} =0.325L

Finally, the molarity turns out:

M=\frac{0.207mol}{0.325L}\\\\M=0.638M

Best regards!

5 0
3 years ago
Hi, can someone help me with this.
AleksAgata [21]
It is 0.5474 but you can put 0.5 hope this helps
4 0
3 years ago
Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
Flauer [41]

Answer:

\boxed{28.81}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

1. Moles of C₄H₁₀

\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

3. Mass of CO₂

\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}

8 0
2 years ago
How many moles of n are in 0.163 g of n2o?
zimovet [89]

First convert 0.163 grams of N2O to mol by dividing it with the molecular weight. The molecular weight of N2O is 44 grams/mol. The answer would be 3,79x10^-3. Then multiply it with 2 since there are 2 Nitrogen in one mole of N2O. Therefore, there are 7.41x10^-3 moles of Nitrogen. 

3 0
3 years ago
Read 2 more answers
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