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docker41 [41]
3 years ago
5

Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate t

he mass of helium that it would take to fill the balloon. Be sure to follow significant figure rules when calculating the answer.
Chemistry
2 answers:
iris [78.8K]3 years ago
7 0

 The mass    of  Helium that it would take  to fill the balloon is  1.1277 grams  of helium

<u><em>calculation</em></u>

<u> </u> mass  = density  x volume

Density  = 1.79  x 10 ⁻⁴ g/ml

Volume  = 6.3 L

  • convert  volume  into ml to make  the unit uniform

 that is  1 L = 1000 ml

             6.3 L =? L

by cross  multiplication

= ( 6.3 L x 1000 ml) / 1 L = 6300 ml


mass  is therefore  = 1.79 x 10⁻⁴ g/ml x 6300  ml= 1.1277 grams

zloy xaker [14]3 years ago
4 0
Density = 1.79x10⁻⁴ g/mL

1  L = 1000 mL

6.3 L = ?  

6.3 x 1000 => 6300 mL

Mass of helium:

m = D x V  

Therefore:

m = ( 1.79x10⁻⁴ ) x  6300

m = 1.1277 g of helium


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The total pressure of gases a, b, and c in a closed container is 4.1 atm. if the mixture is 36% a, 42% b, and 22% c by volume, w
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 The  partial  pressure of  gas C  is 0.902  atm


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partial pressure of gas c  =[( percent by volume of  gas   C /  total  percent)   x total pressure]


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Total   percent  = 36% +42%  + 22%  = 100 %

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What mass of copper is deposited when a current of 10.0a is passed through a solution of copper(ii) nitrate for 30.6 seconds?
asambeis [7]
Data Given:

Time = t = 30.6 s

Current = I = 10 A

Faradays Constant = F = 96500

Chemical equivalent = e = 63.54/2 = 31.77 g

Amount Deposited = W = ?

Solution:
             According to Faraday's Law,

                                          W  =  I t e / F

Putting Values,
 
                            W  =  (10 A × 30.6 s × 31.77 g) ÷ 96500

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Result:
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