The equation is as follows;
2CH3OH(g) = 2CH4(g) + O2(g), ΔH= +252.8 kJ
From the equation; for the reaction to produce 2 moles of methane (32g) an energy of 252.8 kJ is released.
Therefore; for an energy of 82.3 kJ the number of moles that will be produced will be; = (2×82.3)/252.3
= 0.6524 moles
which is equivalent to 0.6524 × 16 = 10.438 g
There, the mass of CH4 produced will be 10.438 g
Answer:
134.397 Joules
Explanation:
Using the formula:
E = C × m × Δθ (where E is Energy, C is specific heat capacity and Δθ is change in temperature)
So E = 0.45×5.45×(79.8-25)
So E = 134.397 Joules
I'm just doing the ones that you don't have numbers already for.
2.) just leave it alone and it's correct
3.) Mg + 2AgNo3 --> Mg(No3)2 + 2Ag
5.) just leave it alone and it's correct
8.) 10C3H8O3 + 15O2 --> 30CO2 + 4H2O
10.) P4 + 6Br2 --> 4PBr3
12.) 2FeCl3 + 6NaOH --> 2Fe(OH)3 + 6NaCl
13.) 2CH3OH + 3O2 --> 2CO2 + 4H2O
14.) 2Al + 3Cu(NO3)2 --> 2Al(NO3)3 + 3Cu
15.) 3CaCl2 + 2K3AsO4 --> Ca3(AsO4)2 + 6KCl
16.) 2NH3 --> N2 + 3H2
17.) 2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O
19.) Mg3N2 + 6H2O --> 3Mg(OH)2 + 2NH3
I hope this helps you!!
It will take the Ne gas approximately 1.2 s to equilibrate between the two sides.
We know that the time taken for a gas to diffuse is dependent on the molar mass of the gas. This is one of the interpretations of Graham's law of diffusion in gases. Thus, Let;
t1 = time taken for Rn to equilibrate = 4.0 s
t2 = time taken for Ne to equilibrate = ?
M1 = molar mass of Rn = 222g/mol
M2 = molar mass of Ne = 20 g/mol
Using
t1/t2 = √M1/M2
4/t2 = √222/20
4/t2 = 3.33
t2 = 4/3.33
t2 = 1.2 seconds
Learn more about diffusion in gases: brainly.com/question/879602
