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crimeas [40]
3 years ago
9

Which particles are located in the nucleus of the atom? (2 points)

Physics
1 answer:
pentagon [3]3 years ago
8 0

Answer:

Neutrons and protons are located in the nucleus of the atom.

Explanation:

And electrons are in the electron cloud.

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ANSWER ASAP!!!If a wave machine produces 10 waves in 2 seconds, what is the frequency of the machine in Hertz?
Rufina [12.5K]

Answer:

5Hz

Explanation:

Frequency = No. of waves per second

10 waves are produced in 2 seconds

in one second 10/2 waves are produced

(ie) 5 waves are produced in 1 second

Therefore the frequency of wave is 5 Hz

4 0
2 years ago
How do mass and force affect the acceleration of an object?
joja [24]

Gravity affects weight, it does not affect mass. Masses always remain the same. Newton's Second Law of Motion: Force = mass x acceleration The acceleration of an object is: a) directly proportional to the net force acting on the object. ... c) inversely proportional to the mass of the object.

3 0
3 years ago
Read 2 more answers
A meter stick balances at the 50.0-cm mark. If a mass of 50.0 g is placed at the 90.0-cm mark, the stick balances at the 61.3-cm
Airida [17]

Answer:

126.99115 g

Explanation:

50 g at 90 cm

Stick balances at 61.3 cm

x = Distance of the third 0.6 kg mass

Meter stick hanging at 50 cm

Torque about the support point is given by (torque is conserved)

mgl_1=Mgl_2\\\Rightarrow M=\dfrac{ml_1}{l_2}\\\Rightarrow M=\dfrac{50\times (61.3-90)}{50-61.3}\\\Rightarrow M=126.99115\ g

The mass of the meter stick is 126.99115 g

6 0
2 years ago
Read 2 more answers
A net force of 60 N north acts on an object with a mass of 30 kg. Use Newton's second law of
earnstyle [38]

Answer:

Explanation:

F = ma. For us, this looks like

60 = 30a and

a = 2 m/s/s

If the force goes up to, say, 90, then

90 = 30a and

a = 3...if the force goes up, the acceleration also goes up.

If the mass goes up to say, 60, and the force stays the same, then

60 = 60a and

a = 1...if the mass goes up, the acceleration goes down.

7 0
3 years ago
A projectile is fired directly upward from the ground with an initial velocity of 112 f/sec its distance s above the ground afte
Travka [436]

Answer:

3.48 seconds

Explanation:

At maximum height Vf=0 m/s

Vf= Vi - g*t

⇒g*t= Vi

⇒t= Vi/g

⇒t= 112/32.17 sec

⇒ t= 3.48 s

so the projectile will achieve its maximum height in 3.48 seconds.

7 0
2 years ago
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