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dezoksy [38]
4 years ago
5

How many milliliters of 2.55M NaOH is needed to make 125mL of 0.75M NaOH solution??

Chemistry
2 answers:
Anna35 [415]4 years ago
5 0

Answer:

36.7 milliliters of 2.55M NaOH will be needed

Explanation:

Molarity of NaOH solution = M_1=2.55 M

V_1=?

Molarity of 125 mL NaOH solution  = M_2=0.75 M

V_2=125 mL = 0.125 L

Using dilution formula :

M_1V_1=M_2V_2

2.55 M \times V_1=0.75 M\times 0.125 L

V_1=0.0367 L = 36.7 mL

36.7 milliliters of 2.55M NaOH will be needed

spin [16.1K]4 years ago
3 0
As i am reading the problem, i notice they give two concentrations (M), a volume and asking for the other volume; this should be a hint that we need to use the dilution formula---> M1V1 = M2V2

M1= 2.55 M
V1= ?
M2= 0.75 M
V2= 125 mL

now, we plug in the values into the formula

(2.55 x V1) = (0.75 x 125)

V1= 36.8 mL
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2 years ago
The three naturally occurring isotopes of potassium are 39K, 38.963707u; 40K, 39.963999u; and 41K.The percent natural abundances
sweet-ann [11.9K]

Answer:

The isotopic mass of 41K is 40.9574 amu

Explanation:

Step 1: Data given

The isotopes are:  

39K with an isotopic mass of 38.963707u and natural abundance of 93.2581%

40K with an isotopic mass of 39.963999u

41K wit natural abundance of 6.7302 %

Average atomic mass =39.098 amu  

Step 2: Calculate natural abundance of 40 K

100 % - 93.2581 % - 6.7302 %

100 % = 0.0117 %

Step 3: Calculate isotopic mass of 41K

39.098 = 38.963707 * 0.932581 + 39.963999 * 0.000117 + X * 0.067302

39.098 = 36.33681 + 0.0046758 +  X * 2.067302

X = 40.9574 amu

The isotopic mass of 41K is 40.9574 amu

8 0
4 years ago
A nickle is about 2 millimeters thick, or 2/1000 of a meter.how many nanometers is this?
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8 0
4 years ago
The reaction is run at two temperatures where temperature 1 is lower than temperature 2. Which relationship is correct for eithe
Tasya [4]

Answer:

The answer is "K_1 < K_2"

Explanation:

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3 years ago
If you dispense 40 ml of hexane, but it turns out you only need 5 ml, what should you do with the remainder?
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After subtracting the volume needed from the volume dispensed, we got a remainder of 35ml

<h3>Subtraction of Numbers</h3>

Given Data

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Let us compute the amount of excess hexane/ the volume that will remain

Remainder = The difference in volume dispensed and the volume needed

Remainder = 40-5

Remainder = 35 ml

The remainder is 35ml

Learn more about subtraction of numbers here:

brainly.com/question/4721701

7 0
3 years ago
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