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11111nata11111 [884]
3 years ago
14

What is an example of a conceptual model in science?

Physics
2 answers:
Elis [28]3 years ago
7 0

A conceptual model is a representation of a system, made of the composition of concepts which are used to help people know, understand, or simulate a subject the model represents.

hope this helps you alot!


jarptica [38.1K]3 years ago
3 0

Answer: A mental image of gas molecule as tiny balls

Explanation:

APEX

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Does the work cause a change in kinetic energy or a potential energy?
Alla [95]

Answer:

Work cause a change in kinetic energy

3 0
3 years ago
The graph in Figure 4.15 shows the position and time for two runners in a race. Who has the faster speed, Robin or Joel? Explain
Burka [1]

Answer:

Joel has the faster speed.

Explanation:

Joel has a steeper slope on the graph. The steeper a slope is, the faster speed will be. Therefore, Joel's slope is steeper which increases overall speed.

4 0
3 years ago
If the initial velocity of an object was -2 meters per second
Shalnov [3]
A :-) for this question , we should apply
a = v - u by t
Given - u = -2 m/s
v = -10 m/s
t = 16 sec
Solution -
a = v - u by t
a = -10 - -2 by 16
a = -12 by 16
( cut 12 and 16 because 2 x 6 = 12 and
2 x 8 = 16 )
( cut 6 and 8 because 2 x 3 = 6 and
2 x 4 = 8 )
a = 3 by 4
a = 0.75 m/s^2

.:. The acceleration is 0.75 m/s^2.
3 0
3 years ago
A spherical balloon is deflating at 10 cm3/s. At what rate is the radius changing when the volume is 1000π cm3 ? What is the rat
just olya [345]

Answer:

1.dr/dt=0.0096cm/s

2. dA/dt=2.19cm^2/s

Explanation:

A spherical balloon is deflating at 10 cm3/s. At what rate is the radius changing when the volume is 1000π cm3 ? What is the rate of change of surface area at this moment?

for this question, we need to analyze the parameters we know

V=volume of the spherical balloon 1000π cm3

volume of the sphere=\frac{4}{3} \pi r^{3}

1000π=4/3πr^3

dividing both sides by 4

250*3=r^3

r=9.08cm, the radius of the balloon

dv/dt=dv/dr*dr/dt...................................1

dv/dr  ,means

V=\frac{4}{3} \pi r^{3}

dv/dr=4*pi*r^2

dv/dt=10 cm3/s

from equ 1

10=4*pi*9.08^2*dr/dt

10=1036 dr/dt

dr/dt=10/1036

dr/dt=0.0096cm/s

2. to find the rate at which the area is changing we have,

dA/dt=dA/dr*dr/dt

area of a sphere is  4πr^2

differentiate a with respect to r, radius

dA/dr=8πr

dA/dt=8πr*0.0096

dA/dt=8*pi*9.08*0.0096

dA/dt=2.19cm^2/s

is the rate of change of the surface area

7 0
3 years ago
A squirrel runs at a speed of 9.9 m, with 25 J of kinetic energy. What is the squirrel’s mass?
adoni [48]

Answer:

The mass of the squirrel is 0.51kg

4 0
3 years ago
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