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Vilka [71]
4 years ago
6

The yellow balls represent neutrons and have a neutral charge. true false

Physics
2 answers:
Paul [167]4 years ago
7 0
Yes the answer is true
Doss [256]4 years ago
6 0
Yes the is true because
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A nonconducting sphere has radius R = 1.81 cm and uniformly distributed charge q = +2.08 fC. Take the electric potential at the
Sloan [31]

Answer:

a) V = -0.227 mV

b) V = -0.5169 mV

Explanation:

a)

Inside a sphere with a uniformly distributed charge density, electric field is radial and has a magnitude

E = (qr) / (4πε₀R³)

As we know that

V = -\int\limits^r_0 {E} \, dr

By solving above equation, we get

V = (-qr²) / (8πε₀R³)

When

R = 1.81 cm

r = 1.2 cm

q = +2.80 fC

ε₀ = 8.85 × 10⁻¹²

V = (-2.80 × 10⁻¹⁵ × (1.2 × 10⁻²)²) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²)³)

V = -2.27 × 10⁻⁴ V

V = -0.227 mV

b)

When

r = R

R = 1.81 cm

q = +2.80 fC

ε₀ = 8.85 × 10⁻¹²

V = (-qR²) / (8πε₀R³)

V = (-q) / (8πε₀R)

V = (-2.80 × 10⁻¹⁵) / (8 × 3.14 × 8.85 × 10⁻¹² × (1.81 × 10⁻²))

V = -5.169 × 10⁻⁴ V

V = -0.5169 mV

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4 years ago
A 60 W bulb is supplied with 36 000 j of energy how long is the bulb on for
antiseptic1488 [7]

Answer:

Time = 600 seconds

Explanation:

Given the following data;

Power = 60W

Energy = 36000

To find the time;

Energy = power * time

Substituting into the equation, we have;

36000 = 60 * time

Time = 36000/60

Time = 600 seconds.

Therefore, the bulb was on for 600 seconds.

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How many squares for three traits?
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