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4 years ago

Which of the following statements about the problem of object recognition is false?

Physics

1 answer:

alexandr1967 [171]4 years ago

6 0

Answer:

The answer is: letter c, in object recognition, the goal is recognizing the proximal stimulus.

Explanation:

Letter c is a "false" statement about object recognition because the goal is recognizing the distal stimulus and "not the proximal stimulus."

Distal stimulus refers to <em>an event or an object in the world that provides information to the proximal stimulus. </em>The proximal stimulus is a pattern of these events and objects that reaches to your senses. They can be registered in the person via<em> "sensory receptors." </em>

We need to recognize the distal stimulus and not the proximal stimulus. For example, when a lemon (distal stimulus) is being cut, it brings out a fragrance (proximal stimulus) that goes to the person's sense of smell. This gives the person a hint on where the smell is coming from and what it is. Then, the person recognizes that it is a lemon.

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A train travels 86 kilometers in 1 hours, and then 98 kilometers in 1 hours. What is its average speed?

Verizon [17]

Answer: average speed = 92 km/h

Explanation:

1) Data:

distance 1 = 86 km
time 1 = 1 hour

distance 2 = 98 km
time 2 = 1 hour

average speed = ?

2) Formula:

average speed = distance / time

3) distance = distance 1 + distance 2 = 86 km + 98 km = 184 km

4) time = time 1 + time 2 = 1 h + 1 h = 2h

5) average speed = 184 km / 2h = 92 km/h

4 0

4 years ago

The volume V of a right circular cylinder of radius r and height h is V=πr2h. (a) How is dVdt related to drdt if h is constant a

Nikolay [14]

Answer:

(a) $\frac{dV}{dt}= 2\pi r h \frac{dr}{dt}$

(b) $\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

(c) $\frac{dV}{dt} = \pi r^2\frac{dh}{dt}+2\pi r h\frac{dr}{dt}$

Explanation:

Differentiating Rules:

$\frac{dx^n}{dx}= nx^{n-1}$
$\frac{dx}{dx}=1$
$\frac{d}{dx}(mn)= m\frac{dn}{dx}+n\frac{dm}{dx}$ [ m and n are the function of x]
$\frac{d}{dx}(cn)=c \frac{dn}{dx}$ [ here c is constant and n is function of x]

Given that,

$V= \pi r^2h$

(a)

$V= \pi r^2h$

Differentiating with respect to t

$\frac{dV}{dt}= \frac{d}{dt}(\pi r^2h)$

$\Rightarrow \frac{dV}{dt}= \pi h \frac{d}{dt}(r^2)$ [ here $\pi h$ is constant]

$\Rightarrow \frac{dV}{dt}= \pi h 2r \frac{dr}{dt}$

$\Rightarrow \frac{dV}{dt}= 2\pi r h \frac{dr}{dt}$

(b)

$V= \pi r^2h$

Differentiating with respect to t

$\frac{dV}{dt}= \frac{d}{dt}(\pi r^2h)$

$\Rightarrow \frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

(c)

$V= \pi r^2h$

Differentiating with respect to t

$\frac{dV}{dt}= \frac{d}{dt}(\pi r^2h)$

$\Rightarrow \frac{dV}{dt} = \pi r^2\frac{dh}{dt}+\pi h\frac{d}{dt}(r^2)$

$\Rightarrow \frac{dV}{dt} = \pi r^2\frac{dh}{dt}+2\pi r h\frac{dr}{dt}$

3 0

4 years ago

A chain saw produces a spherical sound wave having a frequency of 214Hz in air at 358C (308.2K or 958F). At a distance of 600mm

Helen [10]

Given Information:

Frequency = 214 Hz

Temperature = 358° C = 308.2 K

Sound Pressure = p = 100 dB = 2 pascal

Distance = 600 mm = 0.60 m

Required Information:

(a) Acoustic Power Level = ?

(b) Acoustic Particle Velocity = ?

and Velocity level at a distance of 600 mm = ?

Answer:

Acoustic Power Level = Lw = 106.44 dB

Acoustic Particle Velocity = v = 0.0106 m/s

Velocity level = 60.25 dB

Explanation:

(a) Acoustic Power Level

Acoustic Power = W = 4πr² I

Acoustic Intensity = I = p ²/Z₀

Where Z₀ is the characteristic impedance of air Z₀ = 409.8 rayl

I = p ²/Z₀ = (2)²/409.8 = 0.00976 W/m²

W = 4πr² I = 4*π(0.60)²*0.00976 = 0.0441 W

Acoustic Power Level = Lw = 10log(W/Wref)

Where Wref is Reference Acoustic Power Wref = 1x10⁻¹² W

Lw = 10log(W/Wref) = 10log(0.0441/1x10⁻¹²) = 106.44 dB

Lw = 106.44 dB

(b) Acoustic Particle Velocity

Acoustic Particle velocity = v = p ²/Zs

Where Zs is specific acoustic impedance

Zs = Z₀kr/(1 + k²r²)⁰°⁵

Where k = 2πf/c and c = 346.1 m/s is the speed of sound in air

k = 2π*214/346.1 = 3.885 per m

Zs = 409.8*3.885*0.60/(1 + (3.885)²(0.60)²)⁰°⁵

Zs = 376.6 rayl

v = p ²/Zs = 2²/376.6 = 0.0106 m/s

v = 0.0106 m/s

Velocity level = 10log(v/vref) where vref = 10x10⁻⁹ m/s

Velocity level = 10log(0.0106/10x10⁻⁹) = 60.25 dB

Velocity level = 60.25 dB

8 0

4 years ago

In 1958 a large earthquake in Alaska produced a tsunami. What was the approximate height of the tsunami?

lilavasa [31]

The approximate height of the tsunami in Alaska in 1958 is 1720ft

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4 years ago

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Describe how humans’ actions and natural processes have modified coastal regions in Louisiana and other locations

il63 [147K]

Coastal erosion has depleted a large portion of South Louisiana's wetlands along the coastline in swamps and marshes mainly due to storm surges. But other factors also contributed to this erosion. Canals and waterways dug through the marshes and swamps for the oil industry is one factor. Man-made levees erected to provide protection to residents living adjacent to the river is another major cause. Large scale logging especially in the early 1900's also damaged the wetlands.

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4 years ago