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Pavlova-9 [17]
3 years ago
5

Which of the following statements about the problem of object recognition is false?

Physics
1 answer:
alexandr1967 [171]3 years ago
6 0

Answer:

The answer is: letter c, in object recognition, the goal is recognizing the proximal stimulus.

Explanation:

Letter c is a "false" statement about object recognition because the goal is recognizing the distal stimulus and "not the proximal stimulus."

Distal stimulus refers to <em>an event or an object in the world that provides information to the proximal stimulus. </em>The proximal stimulus is a pattern of these events and objects that reaches to your senses. They can be registered in the person via<em> "sensory receptors." </em>

We need to recognize the distal stimulus and not the proximal stimulus. For example, when a lemon (distal stimulus) is being cut, it brings out a fragrance (proximal stimulus) that goes to the person's sense of smell. This gives the person a hint on where the smell is coming from and what it is. Then, the person recognizes that it is a lemon.

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Explanation:

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What might be causing the universe to accelerate?
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what will happen to the brightness of the other bulbs in a series circuit if any of the bulbs were to burn out?
Ivenika [448]

Answer:

not work.

Explanation:

if u are saying in a series circuit...

if 1 build burns out and theres other bulbs the circuit wont work anymore.

6 0
3 years ago
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.0 m/s. Th
elena55 [62]

<u>Answer:</u>

<em>Thunderbird is 995.157 meters behind the Mercedes</em>

<u>Explanation:</u>

It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird  decided to take a pit stop and slows down for 250 m. She spent 5 seconds  in the pit stop.

Here final velocity v=0 \ m/s

initial velocity u= 71 m/s  distance  

Distance covered in the slowing down phase = 250 m

v^2-u^2=2as

a= \frac {(v^2-u^2)}{2s}

a = \frac {(0^2-71^2)}{(2 \times 250)}=-10.082 \ m/s^2

v=u+at

t= \frac {(v-u)}{a}

= \frac {(0-71)}{(-10.082)}=7.042 s

t_1=7.042 s

The car is in the pit stop for 5s t_2=5 s

After restart it accelerates for 350 m to reach the earlier velocity 71 m/s

a= \frac {(v^2-u^2)}{(2\times s)} = \frac{(71^2-0^2)}{(2 \times 370)} =6.81 \ m/s^2

v=u+at

t= \frac{(v-u)}{a}

t= \frac{(71-0)}{6.81}= 10.425 s

t_3=10.425 s

total time= t_1 +t_2+t_3=7.042+5+10.425=22.467 s

Distance covered by the Mercedes Benz during this time is given by s=vt=71 \times 22.467= 1595.157 m

Distance covered by the Thunderbird during this time=250+350=600 m

Difference between distance covered by the Mercedes  and Thunderbird

= 1595.157-600=995.157 m

Thus the Mercedes is 995.157 m ahead of the Thunderbird.

6 0
3 years ago
Which satellite has the greatest gravitational force with Earth?
EastWind [94]

Answer:

Satellite D has a mass (kg) of 500 and the distance from Earth (km) is 320.

Explanation:

The universal law of gravitation states that the force between two objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

We have to choose the satellite having greatest gravitational force with earth. In all options the distance from the earth is same i.e. 320 km. So, we have to select the satellite having maximum mass because the mass of the earth is constant.

Hence, the correct option is (D) " Satellite D has a mass (kg) of 500 and the distance from Earth (km) is 320 ".

5 0
3 years ago
Read 2 more answers
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