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likoan [24]
3 years ago
7

The weight of a body above sea level varies inversely with the square of the distance from the center of Earth. If a woman weigh

s 131 pounds when she is at sea​ level, 3960 miles from the center of​ Earth, how much will she weigh when she is at the top of a​ mountain, 4.8 miles above sea​ level?
Physics
1 answer:
Serjik [45]3 years ago
4 0

Answer:

89.16pounds

Explanation:

The equation that defines this problem is as follows

W=k/X^2

where

W=Weight

K= proportionality constant

X=distance from the center of Earth

first we must find the constant of proportionality, with the first part of the problem

k=WX^2=131x3960^2=2054289600pounds x miles^2

then we use the equation to calculate the woman's weight with the new distance

W=2054289600/(4800)^2=89.16pounds

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From the question we are told that it started from rest so  u = 0 m/s

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