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castortr0y [4]
2 years ago
10

An object moving with a speed of 5m/s comes to rest in 10s after the brakes are applied . What is the initial velocity​?

Physics
1 answer:
Flauer [41]2 years ago
8 0

Initial velocity is 5m/s.

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A car travels from Kathmandu to Hetauda. The distance covered by it in 4hrs is
Ivan

Answer:

50km/hr

Explanation:

speed= distance / time

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3 years ago
I'm giving out a lot of points for whoever helps me and answers correctly! 3 questions to answer! Please answer them ALL!!! :D
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1-a 2-b 3-b    

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5 0
4 years ago
Read 2 more answers
A candy-filled piñata is hung from a tree for Matthew's birthday. During an unsuccessful attempt to break the 4.4-kg piñata, Hay
Margaret [11]

Answer:

The speed of the piñata immediately after being cracked by the stick is v_{fp}=0.59\: m/s.

Explanation:

Using the conservation of linear momentum:

m_{s}v_{is}=m_{p}v_{fp} (1)

Here:

m(s) is the mass of the stick

m(p) is the mass of the piñata

v(is) is the initial velocity of the stick

v(fp) is the final velocity of the piñata        

So, we just need to solve the equation (1) to v(fp).

v_{fp}=\frac{m_{s}v_{is}}{m_{p}}

v_{fp}=\frac{0.54*4.8}{4.4}

v_{fp}=0.59\: m/s

I hope it helps you!

8 0
3 years ago
Which of these choices is a physical property that does not change when the size of the sample changes
Evgen [1.6K]

Answer:

An intensive property is a bulk property, meaning that it is a physical property of a system that does not depend on the system size or the amount of material in the system. Examples of intensive properties include temperature, refractive index, density, and hardness of an object.

4 0
3 years ago
A flat coil of wire consisting of 15 turns, each with an area of 40 cm 2, is positioned perpendicularly to a uniform magnetic fi
zheka24 [161]

Answer:

0.54 A

Explanation:

Parameters given:

Number of turns, N = 15

Area of coil, A = 40 cm² = 0.004 m²

Change in magnetic field, ΔB = 5.1 - 1.5 = 3.6 T

Time interval, Δt = 2 secs

Resistance of the coil, R = 0.2 ohms

To get the magnitude of the current, we have to first find the magnitude of the EMF induced in the coil:

|V| = |(-N * ΔB * A) /Δt)

|V| = | (-15 * 3.6 * 0.004) / 2 |

|V| = 0.108 V

According to Ohm's law:

|V| = |I| * R

|I| = |V| / R

|I| = 0.108 / 0.2

|I| = 0.54 A

The magnitude of the current in the coil of wire is 0.54 A

6 0
3 years ago
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