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Alexeev081 [22]
3 years ago
5

I really need help on this one no clue

Physics
1 answer:
MariettaO [177]3 years ago
7 0
Refraction is the bending of light.
Therefore, the answer would be A, or the first picture.
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A brick is thrown upward from the top of a building at an angle of 10° to the horizontal and with an initial speed of 16 m/s. If
Basile [38]

Answer:

38.47 m

Explanation:

To find the height of the building, we will use the following equation

y_f=y_i+v_{iy}t+\frac{1}{2}at^2

Where yf is the final height, yi is the initial height, viy is the initial vertical velocity, t is the time, and a is the acceleration due to gravity.

If the brick is in flight for 3.1 s, we can say that when t = 3.1s, yf = 0 m. So, replacing

viy = (16 m/s)sin(10) = 2.78 m/s

a = -9.8 m/s²

we get

0=y_i+2.78(3.1)+\frac{1}{2}(-9.8)(3.1)^2

Solving for yi

\begin{gathered} 0=y_i-38.48 \\ y_i=38.48\text{ m} \end{gathered}

Therefore, the height of the building is 38.48 m

6 0
1 year ago
A hydrogen atom is in its ground state when its orbital electron:
Harlamova29_29 [7]
It is in its ground state when its orbital electron is at its lowest energy amount. 
8 0
3 years ago
What is superstring theory?
Stels [109]
Superstring theory is an attempt to explain all of the particles and fundamental forces of nature in one theory by modeling them as vibrations of tiny supersymmetric strings.
4 0
3 years ago
A 40kg rock falls off a cliff that is 50 meters high. How fast is the speed of the rock when it hits the ground
Oksi-84 [34.3K]

31.3m/s

Explanation:

Given parameters:

Mass of rock = 40kg

Height of cliff = 50m

Unknown:

Speed of rock when it hits ground = ?

Solution:

We are going to use the appropriate motion equation to solve this problem

The rock is falling with the aid of gravitational force. The force is causing it to accelerate with an amount of velocity.

  Using;

                      V²  = U² + 2gH

V = unknown velocity

U = initial velocity = O

g = acceleration due to gravity = 9.8m/s²

H = height of fall

since the initial velocity of the bodyg is 0

     V²  = 2gH

    V= √2gH = √2 x 9.8 x 50 = 31.3m/s

learn more:

Velocity brainly.com/question/4460262

#learnwithBrainly

7 0
4 years ago
A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is
harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

Where,

d_g = Depth of glass

n_w = Refraction index of water

n_g = Refraction index of glass

n_{air} = Refraction index of air

d_w = Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})

d'w = 4.041cm

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

3 0
3 years ago
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