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777dan777 [17]
3 years ago
14

What is the kinetic energy of a 400kg house that is racing around a track at 17 meters per second?

Physics
1 answer:
nasty-shy [4]3 years ago
5 0

Kinetic energy = (1/2) (mass) (speed squared)

Kinetic energy = (1/2) (400 kg) (17 m/s)²

Kinetic energy = (1/2) (400 kg) (289 m²/s²)

<em>Kinetic energy = 57,800 Joules</em>

<em></em>

(That's some amazing house.  I'd like to be there to see it.)

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If a lamp has a resistance of 50 ohms and is operated by a p.d. of 10V, find the current flowing through it
NemiM [27]
V=IR therefore I=V/R=10/50=0.2A therefore the current is 0.2 A
4 0
2 years ago
In a darkened room, a burning candle is placed 1.84 m from white wall. A lens is placed between candle and wall at a location th
KATRIN_1 [288]

Answer:

82.4 cm

Explanation:

The object and screen are kept fixed ie the distance between them is fixed and by displacing lens between them images are formed on the screen . In the first case let u be the object distance and v be the image distance

then ,

u + v = 184 cm

In the second case of image formation , v becomes u and u becomes v only then image formation in the second case is possible.

The difference between two object distance ie(  v - u ) is the distance by which lens is moved so

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3 years ago
What happened to the balloon when it was placed on the bottle with the baking soda and vinegar and why
Veseljchak [2.6K]

Answer:

it creates a gas called carbon dioxide. The gas begins to expand in the bottle and starts to inflate the balloon

Explanation:

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8 0
2 years ago
High energy waves have short wave lengths, true or false?
Anna71 [15]
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3 years ago
A diver springs upward from a board that is 2.70 m above the water. At the instant she contacts the water her speed is 10.9 m/s
TiliK225 [7]

Answer:

vo=5.87m/s

Explanation:

Hello! In this problem we have a uniformly varied rectilinear movement.

Taking into account the data:

α =69.2

vf = 10m / s

h=2.7m

g=9.8m/s2

We know we want to know the speed on the y axis.

We calculate vfy

vfy = 10m / s * (sen69.2) = 9.35m / s

We can use the following equation.

vf^{2} =vo^{2}+2*g*h\\

We clear the vo (initial speed)

vo=\sqrt{vf^{2}-2*g*h }

v0=\sqrt{(9.35m/s)^{2}-2*9.8m/s^{2} *2.7m}

vo=5.87m/s

7 0
2 years ago
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