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Anna11 [10]
3 years ago
8

A researcher plans to conduct a study to compare two groups. Based on previous research, she anticipates a medium effect size. S

he does a power analysis with alpha level of .05. This power analysis tells her.
Physics
1 answer:
mojhsa [17]3 years ago
6 0

Answer:

Alpha level of .05 tells her that the results are reliable and correct.

Explanation:

The alpha levels are commonly used in statistical studies to process a <em>system of hypothesis</em>, which must have a principal hypothesis, alternatives hypothesises and a null hypothesis.

In this order of ideas, in every quantitative research we must <u>prove</u> our principal hypothesis by processing the null one. If it results true the null hypothesis we have to support the alternate hypothesis, if it results false we don't support the alternative hypothesis and the principal one results true.

So, in this process researchers need to have some reliability in their results, and there's where the alpha levels come in. These alpha levels represents the percentage of probability <em>to the null hypothesis to be rejected</em>. As minimum is this number, more reliable is the result.

In this case, she used .05 (5%) alpha level, that means the null hypothesis has 5% of probability to be false, it's a small chance, but if it results <em>the null rejected</em>, it means that <em>the result is reliable</em>. Otherwise if we use 40% of alpha level (for example), that means the result isn't reliable because there was a high chance to reject the null hypothesis in the beginning.

It's like if you are participating in a contest and you have 100% of probability to lose, that means your participation is not worth it, because in the beginning you had odds completely against you.

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v = r*w

where r is the radius, and w is the angular velocity.

w = 2*pi*f

where f is the frequency.

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then we have:

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WILL GIVE BRAINLIEST AND 50 POINTS!
7nadin3 [17]

Answer:

1) Current decreases; 2) Inverse proportionally; 3) 1[A]

Explanation:

1)

As we can see as the resistance increases the current decreases, if we take two points as an example, when the resistance is equal to 50 [ohms] the current is equal to 1[amp] and when the resistance is equal to 200 [ohms] the current tends to have a value below 0.5 [amp]. Thus demonstrating the decrease in current.

2)

Inverse proportionally, by definition we know that the law of ohm determines the voltage according to resistance and amperage. This is the voltage will be equal to the product of the voltage by the resistance.

V=I*R\\V = voltage [volts]\\I = current[amp]\\R = resistance [ohms]

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R =\frac{V}{I} \\or\\I=\frac{V}{R}

And whenever we have in a fractional number the denominator the variable we are interested in, we can say that this is inversely proportional to the value we are interested in determining. In this case, we can see from the two previous expressions that both the current and the resistance appear in the denominator, therefore they are inversely proportional to each other.

3)

If we place ourselves on the graph on the resistance axis, we see that at 50 [ohm] will correspond a current value equal to 1 [A].

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