Answer:
0.25
Explanation:
Magnification = image distance/object distance
mag = v/u.................. Equation 1
Given: f = -10 cm ( diverging lens) u = 30 cm.
Where can calculate for the value of v using
1/f = 1/u+1/v
make v the subject of the equation
v = fv/(u-f)..................... Equation 2
Substitute into equation 2
v = -30(10)/(30+10)
v = -300/40
v = -7.5 cm.
substituting into equation 1,
mag = 7.5/30
mag = 0.25
hence the magnification of the wretch = 0.25
IM HERE kdkdorkrkroejrnjejenejr
Given.
force = 16.88 N is
radius = 0.340m
an angular acceleration = 1.20rad/s^2
the formula for torque is
F*r = I*a
where I is moment of inertia
16.88*.34 = I*1.2
I = 4.78Kg-m^2
so rotational inertia I = 4.78Kg-m^2
Maybe show a picture ? I don’t get the question .
To determine the maximum height for the projectile, we can use the timeless kinematics equation

and plug in what we know. For

, we know it is zero because at the highest location of flight, there is no vertical velocity. For

, we know it is

since the vertical component is the sine of the velocity. We need to solve for

, so it is left as-is. Since the only acceleration is

, we can substitute -9.81 into it. Solving for the equation yields a solution of 17.55 m for

.