The balance equation for the reaction between sodium bicarbonate and hydrochloric acid:
The reactants and react in the ratio 1:1. So we use the mass of sodium bicarbonate and molar mass to find the number of moles produced.
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Again we use the fact that the stochiometric ratio are 1:1:1:1:1, hence the moles of are 24.977moles.
So we used the ideal gas law , where P is the pressure, V is the volume, R the gas constant, is and T is the temperature in kelvins. We make V the subject
The answer is supposed to be in L, , so
Answer:
KOH molar mass = 39 + 16 + 1 = 56g
To make 1 L of 1M soln needs 56g KOH
To make 500mL 1M needs 56/2 = 28g
To make 500mL 0.2M needs 28 x 0.2gn:
Reaction
2AgNO₃ + Cu ⇒ Cu(NO₃)₂ + 2Ag
mol silver (Ag): 95.3 : 108 g/mol = 0.882
mol copper nitrate (Cu(NO₃)₂): 82.9 : 187.5 g/mol = 0.441
mol Ag = 2 x mol Cu(NO₃)₂, so 0.441 being the mole basis of the reactants
mol Cu = 0.441
mass Cu = 0.441 x 63.5 g/mol = 28 g
mol AgNO₃ = 0.882
mass AgNO₃ = 0.882 x 170 g/mol = 149.94 g
I’m trying to get things expanded graph explanation
Finding the difference in math usually means to subtract to numbers. In the case of your problem though, I think the correct answer would just be 4...