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jek_recluse [69]
3 years ago
11

A swimmer swims north at 0.10 m/s relative to still water across a river that flows at 0.25 m/s from east to west. Calculate the

swimmer's velocity relative to the riverbank.
Please no guessing.
Showing work is optional but appreciated
Physics
1 answer:
ValentinkaMS [17]3 years ago
7 0
0.15 m/s East
If you follow the equation a=vf-vi/t, you'll discover that subtracting the final velocity, 0.25 m/s, by the initial velocity, 0.10 m/s, and divide by zero, (bc there was no given time) the answer is 0.15 m/s East
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Answer:

The value  is  P  =3.294 \  W

Explanation:

From the question we are that

     The velocity  v  =  0.540  \  m/s

      The  time taken is  t =  27.0 ms  = 27.0 *10^{-3} \ s

     The  total mass of the train is  m  =  610 \ g  =  0.610 \ kg

Generally the average power delivered is mathematically represented as

     P  =\frac{KE }{t}    

     P  =\frac{  \frac{1}{2}  *  m  *  v^2 }{t}    

=>  P  =\frac{  \frac{1}{2}  *  0.610   *   0.540 ^2 }{ 27.0 *10^{-3}}    

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A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0
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The given question is incomplete. The complete question is as follows.

A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0.90 m/s each second. The push force has a horizontal component of 20 N and a vertical component of 25 N downward. Calculate the coefficient of kinetic friction between the box and the floor.

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The given data is as follows.

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Now, we will balance the forces along the y-component as follows.

       N = W + F_{2}

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Now, balancing the forces along the x component as follows.

       F_{1} - F_{r} = ma

        20 - F_{r} = 8.46 \times (-0.9)

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Also, we know that relation between force and coefficient of friction is as follows.

             F_{r} = \mu \times N

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