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jek_recluse [69]
3 years ago
11

A swimmer swims north at 0.10 m/s relative to still water across a river that flows at 0.25 m/s from east to west. Calculate the

swimmer's velocity relative to the riverbank.
Please no guessing.
Showing work is optional but appreciated
Physics
1 answer:
ValentinkaMS [17]3 years ago
7 0
0.15 m/s East
If you follow the equation a=vf-vi/t, you'll discover that subtracting the final velocity, 0.25 m/s, by the initial velocity, 0.10 m/s, and divide by zero, (bc there was no given time) the answer is 0.15 m/s East
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I need help in my physics class and show me how it’s done
Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)

Where | A | is the magnitude of the vector and \alpha is the angle that it forms with the x axis in the opposite direction to the hands of the clock.

In this problem we know the value of Ax and Ay and we need the angle \alpha.

Vector A is in the 4th quadrant

So:

A_x = 6\\\\A_y = -6.5

So:

|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846

So:

Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)

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\alpha = 313 °

Option 4.

4 0
3 years ago
Describe, in terms of the motion of particles in an object​
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Answer:

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Tom [10]

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4 0
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Answer:

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t = 2 Vo sinθ/g

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  = 2.57 seconds

6 0
3 years ago
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