Question

A 200 kg chunck of lead falls from a hight of 30m and smashes into a rigid floor. calculate the increse in internal engery

Answer 1

Answer:

$\Delta E=58800\ J$

Explanation:

Given:

mass of lead chunk, $m=200\ kg$

height of the fall, $h= 30\ m$

• Assuming the collision to be perfectly inelastic the whole kinetic energy of the chunk is lost after the collision.

• Here when the chunk is at the given height it has a potential energy which on falling transforms into kinetic energy of the chunk.

So, increase in the internal energy of the system after the collision is :

$\Delta E=m.g.h$

$\Delta E=200\times 9.8\times 30$

$\Delta E=58800\ J$