Neptune is the farthest front the sun.
-a = 6mh⁻¹ -25 mh⁻¹ / 10s
-a = - 1.9 m h⁻¹ s⁻¹
-a = - sign indicate deceleration.
Answer:
892 Hz or 842 Hz
Explanation:
Given
The frequency of first guitar is 867 Hz
Beat is produced for every 0·04 s
∴ Beat has a time period of 0·04 s
<h3>Beat frequency is defined as the inverse of the time period of the beat </h3>
Beat frequency = 1 ÷ (Time period) = 1 ÷ 0·04 = 25 Hz
Let the frequency of the second guitar be f Hz
<h3>Beat frequency is defined as the absolute difference between the two frequencies</h3>
∴ Beat frequency = (867 - f) or (f - 867)
First case
25 = 867 - f ⇒ f = 842 Hz
Second case
25 = f - 867 ⇒ f = 892 Hz
∴ Possible frequencies of second guitar could be 892 Hz or 842 Hz
Answer:
Answers are below hopefully they're correct and what u need
Explanation:
1. Step 1: Given
The distance is 600 km, since 100(speed) x 6 (time) = 600
2. Step 2: Formula
s = d/t
d = t x s
t = d/s
3. Step 3: Substitue
s = 600/6
d = 100 x 6
t = 600/100
4. Step 4: Solve
600/6 = 100
100 x 6 = 600
600/100 = 6
Step 5: Answer
Therefore, the distance is 600km, the speed or rate is 100 km/hr, and the time is 6hrs.
NUMBER 2
1. Step 1: Given
Distance = 200 m
Rate or speed = 8m/s
Time = ?
2. Step 2: Formula
s = d/t
d = t x s
t = d/s
3. Step 3: Substitue
t = 200/8
s = 200/25
d = 25 x 8
4. Step 4: Solve
200/8 = 25
25 x 8 = 200
200/25 = 8
5. Step 5: Answer
Therefore, the time is 25sec, distance is 200m, and speed or rate is 8m/s
Answer:
yes
Explanation:
because when you shot the ball your applying force to it