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Readme [11.4K]
4 years ago
9

The ostrich, the fastest two-legged land animal, has been clocked at a speed of 19.4m/s when being pursued by a predator. An ost

rich got loose from a ranch in west Texas and is being chased by a coyote (also able to run just as fast) through a 35mph school zone being clocked by the local sheriff. Could the ostrich and coyote get speeding tickets? Assume it is on a school day during school zone hours. *
Physics
1 answer:
DENIUS [597]4 years ago
6 0

Both of them are in big trouble !  I personally would write up each one of them for => no current valid driver's license, => no current vehicle insurance, => no current vehicle emission inspection sticker, => no visible current vehicle, => failure to signal turns, and => speeding in a school zone, since 19.4 m/s is equivalent to 43.4 mph.  

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A 0.500 kg ball is dropped from rest at a point 1.20 m above the floor. The ball rebounds straight upward to a height of 0.700 m
KatRina [158]

To solve this problem we will apply the concepts related to energy conservation. With this we will find the speed before the impact. Through the kinematic equations of linear motion we will find the velocity after the impact.

Since the momentum is given as the product between mass and velocity difference, we will proceed with the velocities found to calculate it.

Part A) Conservation of the energy

mgh = \frac{1}{2} mv^2

v_1 = \sqrt{2gh}

v_1 = \sqrt{2(9.8)(1.20)}

v_1 = 4.84m/s

\therefore v_1 = -4.84/s \rightarrow \text{Negative direction downward}

Part B)  Kinematic equation of linear motion,

v_2^2 = u_0^2 +2a\Delta y

Here

v= 0 Because at 1.5m reaches highest point, so v=0

0 = u_2^2 +2(-9.8)(0.7)

u_2 = 3.7m/s

Therefore the velocity after the collision with the floor is 3.7m/s

PART C) Total change of impulse is given as,

J = P_2 -P_1

J = mU_2-mV_1

J = m(U_2-V_1)

J = (0.5)(3.7-(-4.84))

J = 4.27kg \cdot m/s \rightarrow \text{Upward because is positive}

6 0
4 years ago
Describe the unique role of water in chemical and biological systems.
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Of the important biological molecules only the non-polar lipids (fats and oils) and large polymers (e.g. polysaccharides, large proteins and DNA) do not dissolve. The water acts as a solvent for chemical reactions and also helps transport dissolved
7 0
3 years ago
How many atoms of oxygen are in the product for the double replacement reaction?
Yakvenalex [24]
6 oxygen hope this helped u
4 0
4 years ago
A) A wire made from iron with a cross-section of diameter 0.800 mm carries a current of 14.0 A. Calculate the "areal current den
Veseljchak [2.6K]

Answer:

A) ρ=1.74x10^{26}

B) μ=1.68x10^{29}\frac{electron}{m^3}

C) v=1.03x10^{-3}\frac{m}{s}

D)e=8.99x10^-9

Explanation:

A)

The magnetic field can be find knowing the current is the charge per second

β= \frac{14eC*s}{1.6x10^{-19}C}\\

β= 8.75x10^{19}e*s

Electron density

ρ=\frac{8.75x10^{19}}{\pi*0.400x10^{-3}m} = 1.74x10^{26}

B)

μ= \frac{7.86}{56.2}\frac{g}{cm^3} \frac{mol}{g}*6.022x10^{23}\frac{molecules}{mol} *2 \frac{electron}{molecule}

μ=1.68x10^{23} \frac{electron}{cm^3}= 1.68x10^{29} \frac{electron}{m^3}

C)

The drift speed using last information found

v= \frac{J}{n*q} \\v= \frac{14A}{\pi*((0.40x10^-3)^2)*1.68x10^29*1.60x10^-19)} = 1.03x10^-3(\frac{m}{s} )

D)

To compared the random thermal motion and the current's drift speed

e=\frac{1.03x10^-3}{1.15x10^5} = 8.99x10^-9

8 0
3 years ago
Consider two thin disks, of negligible thickness, of radiusR oriented perpendicular to thex axis such that the x axis runs throu
Veseljchak [2.6K]

Complete question

The complete question is shown on the first and second uploaded image

Answer:∈

Answer to first question is shown on the second uploaded image.

Part B the Answer is:

The ratio  \frac{R}{a} is evaluated to be 49.99

Explanation:

The explanation is shown on the third ,fourth and fifth image.

7 0
4 years ago
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