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aev [14]
3 years ago
11

Acoustics is the study and application of how wildlife navigates at night. true false

Physics
1 answer:
Basile [38]3 years ago
3 0

Answer: False

Acoustics is a branch of physics that studies by means of physical and mathematical models the sound waves (which are classified as mechanical waves), that is, waves that propagate through matter and can not propagate in vacuum.

This study covers the production, transmission, storage, perception and reproduction of sound.

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Calculate the force necessary to accelerate a 10 kg table from<br> O m/s to 4 m/s in 2 seconds.
yanalaym [24]

Answer:

a= v/t

a = 4/2

a = 2 m/s^2

And F = M a

F = 10 × 2

F = 20 N

6 0
3 years ago
Which piece of evidence justifies the sharing of information to form a scientific theory?
klasskru [66]

Answer:

C

Multiple groups of scientist met at a conference to discuss the theory of continental drift

3 0
2 years ago
Four equal masses m are so small they can be treated as points, and they are equally spaced along a long, stiff wire of neglible
anyanavicka [17]

Answer: 5m/L^2

Explanation:

Inertial I = mr^2 where r = distance from axis of rotation, while m is the mass of the object.

I = 2[m(1L/2)^2] + 2[m(3L/2)^2] = 2m×. 25/L^2+ 3m×2. 25/L^2= 0. 5m/l^2 +4. 5m/l^2

= 5m/l^2.

8 0
3 years ago
Now explore friction force. Set the piece of plastic or wood on the table and push it steadily across the tabletop using your fi
photoshop1234 [79]

Answer: Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact

5 0
3 years ago
What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500
padilas [110]

Answer:

I = 1.21x10^-5 A

Explanation:

You are missing the first part of the problem. This is an example, but it will give you the idea of how to solve yours with your data.

The first part is like this:

<em>A      4.0 cm  diameter parallel plate capacitor has a  0.44 m  m    gap. What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000 V/s?</em>

Now with this, we can solve the problem.

In order to do this, we need to use the following expression:

q = CV (1)

Where:

C: Capacitance of a parellel capacitor (in Faraday)

q: charge of plate or capacitor (In coulombs)

V: voltage in Volts.

However, we need is the current, and we have data of potential difference, so, all we have to do is divide the expression between time so:

q/t = CV/t

And the current is q/t, thus:

I = C * V/t (2)

And finally, Capacitance C with two plates of area A separated by a distance d is:

C = Eo*A/d (3)

Where:

Eo = constant equals to 8.85x10^-12 F/m.

A = Area of the plate, in this case, πr²

d = gap of the capacitor.

Let's calculate first the Capacitance using equation (3):

C = 8.85x10^-12 * π * (0.04/2)² / 0.00046 = 2.42x10^-11 F

Now, it's time to use equation (2) and solve for I:

I = 2.42x10^-11 * 500,000

I = 1.21x10^-5 A

5 0
3 years ago
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