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aev [14]
3 years ago
11

Acoustics is the study and application of how wildlife navigates at night. true false

Physics
1 answer:
Basile [38]3 years ago
3 0

Answer: False

Acoustics is a branch of physics that studies by means of physical and mathematical models the sound waves (which are classified as mechanical waves), that is, waves that propagate through matter and can not propagate in vacuum.

This study covers the production, transmission, storage, perception and reproduction of sound.

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Whenever a charged particle encounters a magnetic field, the particle tends to spiral around the magnetic field lines. as it doe
fomenos
The electromagnetic radiation produced when a charged particle moves spirally in a magnetic field is called <span>synchrotron radiation. This phenomenon occurs due to the fact the particle is accelerated radially (due to the presence of the magnetic field), and every charged particle when it is accelerated emits electromagnetic radiation.</span>
4 0
3 years ago
The mass of an ice cube in a dish is 3 grams. What is the mass of the melted ice cube in the same dish mast likely to be
aleksklad [387]
I would think it would be the same if you are weighting the dish and the Ice cube at the same time anyway. Not to sure though I'm a beginner and math is complicated for me sometimes.
4 0
4 years ago
A sun-like star is barely visible to naked-eye observers on earth when it is a distance of 7.0 light years, or 6.6 * 1016 m, awa
igomit [66]

Answer:

At a distance of 1376.49 candle emits 0.2 watt power

Explanation:

Distance between Sun and earth 6.6\times 10^{16}m

Sun emits a power of P=3.8\times 10^{26}watt

Power emitted by candle = 0.20 watt

We know that brightness is given by

B=\frac{P}{4\pi d^2}

So \frac{3.8\times 10^{26}}{4\pi (6\times 10^{16})^2}=\frac{0.20}{4\pi d^2}

3.8\times 10^{26}d^2=7.2\times 10^{32}

d^2=1.89\times 10^6

d=1376.49m

So at a distance of 1376.49 candle emits 0.2 watt power

3 0
3 years ago
Air in a 120 km/h wind strikes head on the face of abuilding 45m wide by 75m high and is brought to rest. if air has a mass of 1
AlekseyPX
From conservation of momentum, the ram force can be calculated similarly to rocket thrust:
 F = d(mv)/dt = vdm/dt.
 <span>In other words, the force needed to decelerate the wind equals the force that would be needed to produce it. 
</span><span> v = 120/3.6 = 33.33 m/s 
</span><span> dm/dt = v*area*density
</span> dm/dt = (33.33)*((45)*(75))*(1.3) 
 dm/dt = <span> 146235.375 </span><span>kg/s 
</span><span> F = v^2*area*density
</span> F = (33.33)^2*((45)*(75))*(1.3) = <span> <span>4874025 </span></span><span>N 
</span> This differs by a factor of 2 from Bernoulli's equation, which relates velocity and pressure difference in reference not to a head-on collision of the fluid with a surface but to a fluid moving tangentially to the surface. Also, a typical mass-based drag equation, like Bernoulli's equation, has a coefficient of 1/2; however, it refers to a body moving through a fluid, where the fluid encountered by the body is not stopped relative to the body (i.e., brought up to its speed) like is the case in this problem.
4 0
4 years ago
Read 2 more answers
Amy walks 3 m from her desk to the teacher's desk. From the teacher's desk, she then walks 4 m in the opposite direction to the
Reptile [31]
I don't know what the tables you have look like but her <span>displacement</span> would be -1m

4 0
3 years ago
Read 2 more answers
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