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Nat2105 [25]
2 years ago
10

Is the following nuclear equation balanced? Yes or No.

Chemistry
2 answers:
4vir4ik [10]2 years ago
5 0

Answer: No

Explanation:

_{85}^{218}\textrm{At}\rightarrow _{84}^{218}\textrm{Po}+_{-1}^0\beta

A balanced nuclear equation is one in which the atomic number and mass number remains same on both sides of the equation i.e the number of protons and neutrons remain same.

In the given equation, the atomic number on left hand side is 85 and the mass number is 218. The atomic number on the right hand side will be (84-1)= 83 and the mass number is (218+0)=218. Thus the equation is not balanced as the mass number is same but the atomic number is different.

Maru [420]2 years ago
3 0

<em>Answer:</em>

  • No

<em>Reason: </em>

  • During a beta decay, one neutron convert into one proton and one electron. The proton remained in nucleus while electron move away known as beta radiation. So atomic mass will be remained same but atomic no will increase by one. So correct ans will be with 218, 86 Po and beta radiation.
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32°F

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Answer:

Mass of HCN produced = 6.75 g

Explanation:

Reaction is as follows:

2NH_3+3O_2+2CH_4 \rightarrow 2HCN + 6H_2O

First calculate the no. of moles of each chemical species.

molecular mass of NH_3 is 17 g/mol

No. of mol of NH_3 = 11.5/17 = 0.676 mol

Molecular mass of O_2 = 32 g/mol

No. of  mol of O_2 = 12/32 = 0.375

Molecular mass of CH_4 = 16 g/mol

No. of  mol of CH_4 = 10.5/16 = 0.656 mol

from the balanced chemical reaction, it is clear that 2-moles ammonia reacts with 3 moles oxygen and 2 moles methane to form 2 moles of HCN.

or, 1-mol ammonia reacts with 1.5 mol oxygen and 1 mol methane to form 1 mol of HCN.

Thus, no. of oxygen present is less than required and so it will act as limiting reagent.

From the chemical equation,

3 moles oxygen produces 2 moles HCN

or one mole oxygen produces (2/3) moles HCN

0.375 moles oxygen produces (2/3) × 0.375 HCN = 0.25 moles of HCN  

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In the Middle Ages, most scientists believed that
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Calculate the molar mass of Ca3(PO4)2<br><br> 934.32 g Ca3(PO4)2 =______ <br> moles Ca3(PO4)2
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Answer:

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Explanation:

The<em> molar mass </em>(MM)<em> of Ca₃(PO₄)₂</em> can be calculated as follows:

  • MM of Ca₃(PO₄)₂ = (MM of Ca)*3 + [(MM of P) +(MM of O)*4]*2
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Now we can <u>convert 934.32 g of Ca₃(PO₄)₂ into moles</u>:

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