Left:
2*g-TL=2*aL
aL=α*0.231
therefore
TL=2*(g-α*0.231)
Right:
TR-1.4*g=4*aR
aR=α*0.272
therefore
TR=1.4*(g+α*0.272)
Wheels:
TL*0.231-TR*0.272=
(2*0.231^2+2.3*0.272^2)*α
combine and solve for α
Answer:
Work done, W = 0.0219 J
Explanation:
Given that,
Force constant of the spring, k = 290 N/m
Compression in the spring, x = 12.3 mm = 0.0123 m
We need to find the work done to compress a spring. The work done in this way is given by :
W = 0.0219 J
So, the work done by the spring is 0.0219 joules. Hence, this is the required solution.
Answer:
Explanation:
Magnetic field at a a point R distance away
B = μ₀ / 4π X 2I / R where I is current
Magnetic field due to one current
= 10⁻⁷ x 2 x 24 / 1 x 10⁻³
48 x 10⁻⁴ T
Magnetic field due to other current
= 10⁻⁷ x 2 x 24 / 3x 10⁻³
16 x 10⁻⁴ T
Total magnetic field , as they act in opposite direction, is
= (48 - 16 ) x 10⁻⁴
32 x 10⁻⁴ T .
Shelli will most likely say that the sound produced by the resonance of a metal is affected by the frequency at which the metal is vibrated. There is a certain frequency that will create a dim sound. If the frequency is changed to the right setting, the sound will intensify.
