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denpristay [2]
3 years ago
8

Maria is baking cookies. She mixes water, flour, sugar, baking powder, butter and chocolate chips and then measures the mass of

her ingredients. The mixture has a mass of 1053 grams. Maria baked the cookies for 15 minutes and then measured the mass of the cookies and found they now had a mass of 845 grams. Why didn't the cookies obey the law of conservation of mass?
Group of answer choices
Chemistry
1 answer:
gladu [14]3 years ago
4 0

Answer:

Cookies definitely obeys the law of conservation.`

Explanation:

As, When Maria mixes up the ingredients, Water was also one among them

And, Initially When she was measuring the weight of Ingredients, Weight of Water was coming,

But,

 When She baked the cookies , water from the cookies got evaporated , and thus weight coming was decreased finally.

Considering Cookies and Environment Whole as a system You can clearly say  that they obeys Law of conservation of mass , As Water is present in Environment for now.

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2.93 mol of MgF2 to grams
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The mass of 1.72 mol of magnesium fluoride is 107 grams.

To determine the mass of 1.72 mol of magnesium fluoride, we first need the chemical formula of magnesium fluoride. Magnesium forms a +2 ion (Mg+2) and fluoride forms a -1 ion (F-1). Since all compounds formed from ions have to be electrically neutral, we need 2 fluoride ions and 1 magnesium ion. Therefore, the formula for magnesium fluoride is MgF2.

Now we need to determine the molar mass of the compound from the molar mass values from the periodic table. Let's use a table to calculate this molar mass.

Molar mass of MgF2

Element Molar Mass (g/mol) Quantity Total (g/mol)

Mg 24.31 1 24.31

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Total molar mass of MgF2 = 24.31 g/mol + 38.00 g/mol = 62.31 g/mol

This is the mass of one mole of the substance. If we have 1.72 mols of it, we multiply 1.72 by 62.31.

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We rounded to 107 to keep the correct number of significant digits in our answer.

8 0
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During a synthesis reaction, 1.8 grams of magnesium reacted with 6.0 grams of oxygen. What is the maximum amount of magnesium ox
skelet666 [1.2K]

Answer:

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Explanation:

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<em>Mg + 1/2O₂ → MgO,</em>

1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.

  • We need to calculate the no. of moles of (1.8 g) of Mg and (6.0 g) of oxygen:

no. of moles of Mg = mass/molar mass = (1.8 g)/(24.3 g/mol) = 0.074 mol.

no. of moles of O₂ = mass/molar mass = (6.0 g)/(16.0 g/mol) = 0.375 mol.

<em>So. 0.074 mol of Mg reacts completely with (0.074/2 = 0.037 mol) of O₂ which be in excess.</em>

<em></em>

<em><u>Using cross multiplication:</u></em>

1.0 mole of Mg produce → 1.0 mol of MgO.

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