Just for more clarification, lowercase k is the rate constant. Uppercase K is the equilibrium constant. You can actually use k to find K (equilibrium constant). K=k/k' This means that the equilibrium constant is the rate constant of the forward reaction divided by the rate constant of the reverse reaction
Agar is used to assist establish an anaerobic environment that promotes nitrate reduction.
Nitrate Reduction test:
- The nitrate in the broth is converted to nitrite by organisms that can produce the nitrate reductase enzyme, which can then be further converted to nitric oxide, nitrous oxide, or nitrogen.
- Anaerobic respiration and denitrification are two processes that can convert nitrate to a variety of compounds.
- While denitrification only reduces nitrate to molecular nitrogen, anaerobic respiration employs nitrate as the bacterium's final electron acceptor, reducing it to a range of chemicals.
- The nitrate reduction test is based on the detection of nitrite and its capacity to produce a red precipitate (prontosil), which is a water-soluble azo dye, when it combines with sulfanilic acid to create a complex (nitrite-sulfanilic acid).
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Answer:
they are big chunks of the earth that are constantly vibrating
Explanation:
Answer:
1.The electrode on the right is positive
2. 0.058V
Explanation:
The above cell is a concentration cell.
A concentration cell is an electrolytic cell that is made of two half-cells with the same electrodes, but differs in concentrations of the solutions. A concentration cell functions by diluting the more concentrated solution and concentrating the more dilute solution, creating a voltage as the cell reaches an equilibrium thereby transferring the electrons from the cell with the lower concentration to the cell with the higher concentration.
In the above cell, electrons flow from the left electrode (less concentrated) to the right electrode (more concentrated). Therefore, the right electrode is the positive electrode (cathode).
Part 2: Please, see the attachment below for the calculations.
Answer:
1/10 or 0.1
Explanation:
Quantities at which equivalence can be obtained are:
95, 96, 97, 98, 99, 100, 101, 102, 103, 104
Number of quantities = N = 10
Probability that the equivalency is obtained exactly at 100 mL can be calculated as follows:
P(X = 100) = (Number of favourable outcomes) / (Total Number of Outcomes)
P(X = 100) = 1/10
P(X = 100) = 0.1
