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Anton [14]
3 years ago
8

In a certain region of space, a uniform electric field has a magnitude of 4.30 x 104 n/c and points in the positive x direction.

find the magnitude and direction of the force this field exerts on a charge of +6.80 μc.
Physics
1 answer:
denis23 [38]3 years ago
5 0
The magnetic force exerted by a field E to a charge q is given by F=Eq. In this case, F=4.30*10^4*(6.80mu C). 1mu C=10^-6C, so F=4.30*6.80=10^-2=0.29N. The direction is in the x direction, the direction that the field is applied because the charge is positive.
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What form of energy is released into the atmosphere by the earth's surface
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Answer:

Thermal Energy (Heat)

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just olya [345]

Based on the calculations, the average velocity is equal to 360 m/s and the percent difference is equal to 4.72%.

<h3>What is average velocity?</h3>

An average velocity can be defined as the total distance covered by a physical object divided by the total time taken.

<h3>What is an average?</h3>

An average is also referred to as mean and it can be defined as a ratio of the sum of the total number in a data set to the frequency of the data set.

<h3>How to calculate the average velocity?</h3>

Mathematically, the average velocity for this data set would be calculated by using this formula:

Average = [F(v)]/n

Vavg = [v₁ + v₂ + v₃ + v₄ + v₅)/5

Since the values of the average velocity from the table are missing, we would assume the following values for the purpose of an explanation:

  • v₁ = 100 m/s
  • v₂ = 150 m/s
  • v₃ = 200 m/s
  • v₄ = 250 m/s
  • v₅ = 300 m/s

Substituting the parameters into the formula, we have:

Vavg = [300 + 450 + 500 + 250 + 300)/5

Vavg = 1800/5

Vavg = 360 m/s.

Next, we would calculate the percent difference by using this formula:

Percent \;difference = \frac{[V_{avg}\;-\;V_{sound}]}{V_{sound}} \times 100

Percent difference = [360 - 343]/360 × 100

Percent difference = 17/360 × 100

Percent difference = 0.0472 × 100

Percent difference = 4.72%.

Read more on average here: brainly.com/question/9550536

#SPJ1

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Two light bulbs have resistances of 400 Ω and 800 ΩThe two light bulbs are connected in series across a 120- V line. Find the cu
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R_{eq}=R_1 + R_2 = 400 \Omega + 800 \Omega=1200 \Omega

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I=\frac{V}{R_{eq}}=\frac{120 V}{1200 \Omega}=0.1 A

And since the two bulbs are connected in series, the current through each bulb is the same.

2) 4 W and 8 W

The power dissipated by each bulb is given by the formula:

P=I^2 R

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For the first bulb:

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P_1 = (0.1 A)^2 (800 \Omega)=8 W

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3 years ago
The average distance from the sun to Pluto is approximately 6.10 × 109 km. How long does it take light from 
Scorpion4ik [409]
V= \frac{S}{t}
t= \frac{S}{V}<u />
t= \frac{S}{c}
t= \frac{6.1*10^{12}}{299792458}
t=20347.4098071s

It takes 20347.4098071s for light from the sun to reach Pluto.
The 6.1*10^9 is replaced by 6.1*10^12 on line 4 because we convert the distance from km to m. 
c = speed of light. If a different value was given in the previous question then use that instead of the value I used to do the final calculation.
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3 years ago
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