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3 years ago

STATE TRUE OR FALSE

Chemistry

1 answer:

AfilCa [17]3 years ago

6 0

<h2>Answer:</h2><h2>T.rue </h2><h2>False .</h2><h2>T.rue </h2><h2>F.alse </h2><h2>F.alse </h2><h2 />

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2NBr3 + 3NaOH = N2 +3NaBr + 3HOBr

bija089 [108]

The theoretical proportion is given by the balanced chemical equation:

2 mol NBr / 3 mol Na OH

Then x mol NaOH / 40 mol NBr3 = 3mol NaOH/2 mol NBr3

Solve for x, x = 40 * 3/2 = 60 mol NaOH.

Given that there are 48 mol NaOH (less than 60) this is the limitant reactant and the other is the excess reactant.

Answer: NBr3..

6 0

3 years ago

Read 2 more answers

The sodium salt, NaA, of a weak acid is dissolved in water; no other substance is added. Which of these statements (to a close a

ddd [48]

Answer:

Your question is somewhat poorly worded, even so what I can contribute is the statement is false, since the salt is sodium chloride, where its severe chemical formula NaCl, is a SALT not an acid and if it dissolves in water, seriously the solute of a solution, where water plays the role of the solvent

Explanation:

Sodium chloride is a binary salt, very easy to dissolve in water, it is also called the famous table salt, since it can be ingested in food even though it is not so recommended against high blood pressure conditions.

8 0

3 years ago

The blank solution used to calibrate the spectrophotometer is 10.0 mL of 0.2 M Fe(NO3)3 diluted to 25.0 mL with 0.1 M HNO3. Why

Sliva [168]

<span>FeNCS+ product...............thats how you do it i believe </span>

4 0

3 years ago

Alkaline batteries are non-rechargeable.<br> Why do alkaline batteries eventually stop working?

scoray [572]

Answer:

Alkaline batteries stop working when all of the manganese dioxide has been converted.

Explanation: Hope it helps you :)))

Have a good day

4 0

2 years ago

A chemistry graduate student is given 500. mL of a 0.20 M chloroacetic acid (HCH2ClCO2) solution. Chloroacetic acid is a weak ac

zhenek [66]

Answer:

12 g of choloracetic acid

Explanation:

The buffer equilibrium is:

HCH₂ClCO₂ ⇄ CH₂ClCO₂⁻ + H⁺

pka= -log ka =

Ka: 1,3x10⁻³ = [CH₂ClCO₂⁻] [H⁺] / [HCH₂ClCO₂]

By Henderson-Hasselbalch equation:

pH = pka + log₁₀ [A⁻] / [HA]

3,01 = 2,89 + log₁₀ [A⁻] / [HA]

1,318 = [A⁻] / [HA]

As molar concentration of chloroacetic acid (HA) is 0,20M

[A⁻] = 0,26 mol/L

The volume is 500 mL ≡ 0,5 L

0,26mol/L × 0,5 L = 0,13 moles of chloroacetic acid. In grams:

0,13 mol × (94,5g / 1mol) = <em>12 g of choloracetic acid</em>

I hope it helps!

3 0

4 years ago