I need help on this.

The diagram below shows the different phase transitions that occur in matter. Three bars are shown labeled Solid, Liquid, and Ga

Grace [21]

The arrow that will represent the phase change that involves the same amount of energy as arrow 1 will be arrow 4.

<h3>Phase change</h3>

Arrow 1 represents a phase change from liquid to gas while arrow 4 represents a phase change from gas to liquid.

In other words, arrow 1 and arrow 4 are direct opposites of one another,

This means that if X amount of energy is required for arrow 1, the same amount of energy will be needed for arrow 4 but in the reverse direction.

More on phase change can be found here: brainly.com/question/12390797

#SPJ1

5 0

1 year ago

Why are elements organized in the same group or families

VladimirAG [237]

The vertical columns on the periodic table are called groups or families<span> because of their similar chemical behavior. All the members of a </span>family<span> of </span>elements<span> have the</span>same<span> number of valence electrons and similar chemical properties</span>

5 0

2 years ago

Read 2 more answers

An 80g sample of 3 1 H decays, leaving 2.5g of 3 1 H.

RUDIKE [14]

Here is the link to the answer:

7 0

3 years ago

Hydrogen and iodine react to form hydrogen iodide, like this: H_2 (g) + I_2 (g) rightarrow 2 HI(g) Also, a chemist finds that at

telo118 [61]

This is an incomplete question, here is a complete question.

Hydrogen and iodine react to form hydrogen iodide, like this:

$H_2(g)+I_2(g)\rightarrow 2HI(g)$

Also, a chemist finds that at a certain temperature the equilibrium mixture of hydrogen, iodine, and hydrogen iodide has the following composition:

Compound Pressure at equilibrium

$H_2$ 61.8 atm

$I_2$ 46.5 atm

$HI$ 52.3 atm

Calculate the value of the equilibrium constant $K_p$ for this reaction. Round your answer to 2 significant digits.

Answer : The value of equilibrium constant $K_p$ for this reaction is, 0.952

Explanation :

The given chemical reaction :

$H_2(g)+I_2(g)\rightarrow 2HI(g)$

The expression of $K_p$ for above reaction follows:

$K_p=\frac{(P_{HI})^2}{P_{H_2}\times P_{I_2}}$

We are given:

$P_{H_2}=61.8atm$

$P_{I_2}=46.5atm$

$P_{HI}=52.3atm$

Putting values in above equation, we get:

$K_p=\frac{(52.3)^2}{61.8\times 46.5}\\\\K_p=0.952$

Therefore, the value of equilibrium constant $K_p$ for this reaction is, 0.952

7 0

2 years ago

The ________ ion is represented by the electron configuration [ar]3d2.

Tresset [83]

The Ti 2+ ions is represented by electron configuration (Ar)3d2. Titanium is in atomic number 22 and its electronic configuration is (Ar)3d2 4s2. Titanium loss two electron that is 4s2 electrons hence the electronic configuration ( Ar)3d2. 4s2 is the valence electron hence it the one which is lost to form Ti2+

3 0

3 years ago

Read 2 more answers